Answer:
t = 49.20 years
Explanation:
Half life expression for first order kinetic is:
Half life = 12.3 years
Where, k is rate constant
So,
The rate constant, k = 0.05635 years⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
is 6.25 % of . So,
= 0.0625
t = ?
<u>t = 49.20 years</u>
Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
Answer:
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Answer:
54 g is the theoretical yield
Explanation:
This is the reaction:
2H₂ + O₂ → 2H₂O
So 2 moles of hydrogen react with 1 mol of oxygen, to produce 2 mol of water.
If I have 3 moles of H₂ and 2 moles of O₂, the my limiting reactant is the hydrogen.
1 mol of O₂ react with 2 moles of H₂
S 2 mol of O₂ would react with 4 moles (I only have 3 moles)
Then, ratio is 2:2 the same as 1:1
As 2 mol of H₂ produce 2 moles of water, 3 moles of H₂ will produce 3 moles of H₂O.
This is the theoretical yield in moles. Let's convert them to mass (mol . molar mass)
3 mol . 18g/m = 54 g