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Alla [95]
4 years ago
14

s sample of thorium-234 has a half life of 25 days. will all the thorium undergo radioactive decay in 50 days?

Chemistry
1 answer:
Assoli18 [71]4 years ago
5 0

Answer:

25% thorium will left after 50 days.

Explanation:

Half life:

A nuclear half is the time period of radioactive material in which its amount remain halved.

In given question it is stated that the half life thorium-234 is 25 days. Which means after passing the 25 days the amount of thorium must be halved of original amount.

For example,

If the original concentration was 100%, than after 25 days it will be 50%.

After 50 days amount of thorium left:

Number of half life = T (elapsed) / T half life

Number of half life = 50/25

Number of half life =  2

At first half life amount of thorium left = 100/2 = 50

After second half life amount of thorium left = 50/2 = 25

Total amount decayed = 50+25 = 75

Amount left after 50 days = 100-75 = 25

25% thorium will left after 50 days.

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The Lewis structure of PF3 shows that the central phosphorus atom has one non bonding and three bonding electron pairs. In this compound each Phosphorus atom contributes 5 valence electrons while each fluoride contributes 7 valence electrons making a total of 26 valence electrons. The central Phosphorus atom forms single bonds with each of the fluoride atoms. Phosphorus, therefore ends up with a non-bonding pair since the fluoride atoms already have 8 electrons around them. <span />
6 0
3 years ago
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How many grams of Na2SO4 can be produced from 423.67 g of NaCl?
san4es73 [151]

Mass of  Na2SO4= 514.18 grams

<h3>Further explanation</h3>

Given

423.67 g of NaCl

Required

mass of  Na2SO4

Solution

Reaction

2NaCl + H2SO4 → Na2SO4 + 2HCl

mol NaCl :

= 423.67 g : 58.5 g/mol

= 7.24

From the equation, mol Na2SO4 :

= 1/2 x mol NaCl

= 1/2 x 7.24

= 3.62

Mass  Na2SO4 :

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= 514.18 grams

4 0
3 years ago
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sweet-ann [11.9K]

Answer:

F. a dark solid formed on the zinc.

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8 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!
GREYUIT [131]
They each have one valence electron in their outer shell, but they are also on the same row (period). If you follow this pattern, potassium will also have one valence electron.

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5 0
3 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
Sonja [21]

Answer:

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

Explanation:

The formula we are going to use is:

N_{Au}=\frac{N_A*C_{Au}}{{\frac{C_{Au}A_{Au} }{\rho_{Au}}}+\frac{A_{Au}}{\rho_{Ag}}(100-C_{Au})}

Where:

N_{Au} are number of gold atoms.

N_A is Avogadro Number.

C_{Au} is the amount of gold.

A_{Au} is the atomic weight of gold.

\rho_{Au} is the density of gold.

\rho_{Ag} is the density of silver.

C_{Ag} is the amount of silver.

N_{Au}=\frac{6.023*10^{23}*45\%wt}{\frac{45\%wt*196.97}{19.32}+\frac{196.97}{10.49}(100-45\%wt)}\\ N_{Au}=1.81718*10^{22}\ atoms/cm^3

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

5 0
3 years ago
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