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shepuryov [24]
3 years ago
6

You have run an experiment studying the effects of the molecular weight of a compound on the rate of diffusion in agar. Compound

X has a molecular weight of 25.3 g/mol and compound Y has a molecular mass of 156.2 g/mol. On two separate agar plates, 0.1 g of each substance were transferred and allowed to diffuse for 2 hours. The results below were obtained. Use this information about this situation to answer the following three questions.
a. What was the independent variable in this experiment?
b. What was the independent variable in this experiment?
c. List two controls that were held constant for this experiment or that you would hold constant for this experiment
Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

A) Molecular weight

B) Rate of diffusion

C) Agar plates

Time of diffusion

Explanation:

A) The independent variable is the molecular weight because it is the variable that the researcher changes at will to aid his research. It doesn't depend on other variables.

B) The dependent variable is "Rate of diffusion because it depends on the molecular weight of the compound.

C) A control variable is one that would be held constant throughout the research.

In this case, the agar plates and the time of 2 hours diffusion remain the same throughout.

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Why do liquids flow but solids dont
taurus [48]
Liquids flow because its particles can move over each other.  The particles have freedom to move and they will keep moving until it takes the shape of its container. 

Solid particles are rigid and tightly packed, they cannot move, so it does not flow.
5 0
3 years ago
What is a face atom?
gavmur [86]

Answer:

Explanation:

An atom on a face is shared by two unit cells, so only half of the atom belongs to each of these cells. An atom on an edge is shared by four unit cells, and an atom on a corner is shared by eight unit cells.

3 0
3 years ago
Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n) ____.
Ugo [173]

<u><em>Answer:</em></u>

It was a positive ion.

<u><em>Explanation</em></u>

In CaBr, ionic bond is present. When one of the atom loses electrons and gets positive charges and other atom gains electrons and become negative. As a result of positive and nagative charges , a ionic bond formed.

As in this case, Ca loses electrons and become positive ion while on the other hand bromide gets the electrons and become negative ion.

<em>Note:</em>

Electropositive atoms always loose electrons Like Ca while electronegative atoms always gain elelctrons like Br.

5 0
4 years ago
Read 2 more answers
You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m
Leona [35]

Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, n_{Mg}, is given as follows;

n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

8 0
3 years ago
How many molecules of manganese (IV) sulfate are there if you are given 542.32g?
MAVERICK [17]

Answer:

3.47 mol MnSO4

Explanation:

54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4

542.32g / 151.01g/mol = 3.47 mol MnSO4

5 0
3 years ago
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