Answer:
It will take 3.3 s for [NOCl] to decrease to 0.042 M.
Explanation:
Integrated rate law for this second order reaction-
![\frac{1}{[NOCl]}=kt+\frac{1}{[NOCl]_{0}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BNOCl%5D%7D%3Dkt%2B%5Cfrac%7B1%7D%7B%5BNOCl%5D_%7B0%7D%7D)
where, [NOCl] is concentration of NOCl after "t" time, ![[NOCl]_{0}](https://tex.z-dn.net/?f=%5BNOCl%5D_%7B0%7D)
is initial concentration of NOCl and k is rate constant.
Here, = 0.076 M, k = 3.2 
and [NOCl] = 0.042 M
So, ![\frac{1}{0.042M}=[3.2M^{-1}s^{-1}\times t]+\frac{1}{0.076M}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.042M%7D%3D%5B3.2M%5E%7B-1%7Ds%5E%7B-1%7D%5Ctimes%20t%5D%2B%5Cfrac%7B1%7D%7B0.076M%7D)
or, t = 3.3 s
So, it will take 3.3 s for [NOCl] to decrease to 0.042 M.
Answer:
that they all dissolved went on watef
Answer:
Some G proteins activate adenylate cyclase, while others inhibit it.
Explanation:
G proteins helps in the signal transduction process that transfer message in the body. GPCRs (G-protein-coupled receptors) are located on the surface membrane of the cell.
The G protein can activates the protein or might deactivate the proteins that helps in the adenylate cyclase. The particular phosphorylation and dephosphorylation process at different sites by the G proteins can result in activation and inactivation of adenylate cyclase.
Thus, the correct answer is option (C).
Moles(AL)/moles(CL2) = 2/3
moles(CL2) = 3/2 * 3.90
moles(CL2) = 5.85 mol
