Answer:
7.568g of CO₂ will be produced
Explanation:
Based on the reaction:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
<em>Where 1 mole of C₃H₈ react with 5 moles of O₂ to produce 3 moles of CO₂ and 4 moles of H₂O</em>
Moles of C₃H₈ and O₂ are:
C₃H₈: 39.0g ₓ (1mol / 44.1g) = 0.884 moles
O₂: 11.0g ₓ (1mol / 32g) = 0.344 moles
For a complete reaction of 0.884 moles of C₃H₈ are necessaries:
0.884 mol C₃H₈ ₓ (6 mol O₂ / 1 mol C₃H₈) = 5.304 moles of O₂
As you have just 0.344 moles of O₂, it is the limiting reactant.
And moles of CO₂ produced are:
0.344 mol O₂ ₓ (3 mol CO₂ / 6 mol O₂) = <em>0.172 moles of CO₂</em>
Thus, mass in grams of CO₂ (44g / mol) is:
0.172 moles of CO₂ ₓ (44g / mol) = <em>7.568g of CO₂ will be produced</em>
