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Softa [21]
3 years ago
11

I really need someone to explain how to find the average atomic mass.... the gizmos was really confusing because they also had w

eighted mass.

Chemistry
1 answer:
evablogger [386]3 years ago
5 0

Answer:

Option C. 52.057

Explanation:

The following data were obtained from the question:

Isotope >> Mass number > Percentage

A (Cr-50) > 50 >>>>>>>>>> 4.3

B (Cr-52) > 52 >>>>>>>>>> 83.8

C (Cr-53) > 53 >>>>>>>>>> 9.5

D (Cr-54) > 54 >>>>>>>>>> 2.4

Average atomic mass =?

The average atomic mass of chromium, Cr can be obtained as follow:

Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]

Atomic mass of Cr = [50×4.3)/100] + [52×83.8)/100] + [53×9.5)/100] + [54×2.4)/100]

= 2.15 + 43.576 + 5.035 + 1.296

Atomic mass of Cr = 52.057

Therefore, the atomic mass of chromium, Cr is 52.057

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You have selected your two primers and added all of the PCR components to a test tube. Use the answer choices [A-C] to explain w
tankabanditka [31]

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7 0
3 years ago
Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Neko [114]

Answer:

104.352°C

Explanation:

Data Given:

Boiling point of water = 100.0°C

Kb (boiling point constant = 0.512°C/m

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Solution:

Formula Used to find out boiling point

               ΔTb = m.Kb . . . . . . (1)

where

               ΔTb = boiling point of solution - boiling point of water

So,

we can write equation 1 as under

               ΔTb = Tb (Solution) -Tb (water)

As we have to find out boiling point so rearrange the above equation

              Tb (Solution)  = m.Kb + Tb (water) . . . . . . . (2)

Put values in Equation 2

            Tb (Solution)  = (8.5 m x 0.512°C/m ) + 100.0°C

            Tb (Solution)  = 4.352 + 100.0°C

            Tb (Solution)  = 104.352°C

so the boiling point of Mg₃(PO₄)₂  8.5 m solution =  104.352°C

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