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Blizzard [7]
3 years ago
10

Formic acid (HCO2H, Ka = 1.8 × 10-4) is the principal component in the venom of stinging ants. What is the molarity of a formic

acid solution if 25.00 mL of the formic acid solution requires 39.80 mL of 0.0567 M NaOH to reach the equivalence point?
Chemistry
1 answer:
DENIUS [597]3 years ago
6 0

Answer : The molarity of a formic acid solution is, 0.0903 M

Explanation :

To calculate the molarity of formic acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of formic acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of sodium hydroxide base which is NaOH.

As we are given:

n_1=1\\M_1=?\\V_1=25.00ml\\n_2=1\\M_2=0.0567M\\V_2=39.80ml

Now put all the given values in above equation, we get:

1\times M_1\times 25.0ml=1\times 0.0567M\times 39.80ml\\\\M_1=0.0903M

Hence, the molarity of a formic acid solution is, 0.0903 M

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What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a<br> 0.75 L solution? *
Korolek [52]

Answer:

M = 16.8 M

Explanation:

<u>Data:</u> HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

M=\frac{moles}{solution volume}

The data is replaced in the given equation:

M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}

7 0
3 years ago
Read 2 more answers
a. Calculate the pH of a solution that has [H3O+]= 4.3 x 10-5 M. b. Is the solution acidic or basic? How do you know?
Luda [366]

Answer:

* pH=4.37

* The solution is acidic since the pH is below 7.

Explanation:

Hello,

In this case, we can mathematically define the pH by:

pH=-log([H_3O^+])

Thus, for the given hydronium concentration we simply compute the pH:

pH=-log(4.3x10^{-5})=4.37

Thereby, we conclude the solution is acidic due to the fact that the pH is below 7 which is the neutral point and above it the solutions are basic.

Regards.

3 0
2 years ago
A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation
qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

\lambda_{max}=\frac{b}{T}

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K  }{0.21m} =0.014K

8 0
3 years ago
If 185 mg of acetaminophen were obtained from a tablet containing 350 mg of acetamino- phen, what would be the weight percentage
Alex73 [517]

Percentage recovery gives us an idea of the amount of pure substance recovered after the chemical reaction. Percentage recovery can be more than 100 % or less than 100 %. Usually, in any experiment performed the weight percentage recovery will be less than 100. Percent recovery values greater than 100 show that the recovered compound is contaminated.

Amount of acetaminophen initially taken = 350 mg

Amount of acetaminophen obtained after recovery =185 mg

Weight percentage recovery =\frac{mass recovered}{mass originally taken}*100

                                                = \frac{185 mg}{350 mg}*100

                                               = 52.9%

8 0
3 years ago
If after heating the reaction between magnesium and hydrochloric acid, the mass of the magnesium chloride and beaker is measured
Allushta [10]

Since the beaker was heated we can asume that only magnesium cloride is left in the beaker, therfore the difference between the beaker with magnesium chloride and the empty beaker give the mass of magnisium chloride:

\text{mass MgCl}_2=massbeakerwithMgCl_2-mass\text{ emprty beaker =37.83 g - 33.95g = 3.8}8g

7 0
1 year ago
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