The solution for this problem is:
The information given lacks but nevertheless the answer is:
So, the total heat free by dissolving the solute was 1386 + 32 = 1417 J
Then, dissolving of the solute will have released -1417 J. So, per gram of Al2
(SO4)3 dissolved:
-1417 J / 25 g = -56.7 J/g
Translating that to a per mole: -56.7 J/g X 342 g/mol = -1.94X10^4 J/mol = -19
kJ/mol = this would be Delta Hsoln
Answer:
81% Yield
Explanation:
2CO + O₂ => 2CO₂
Excess 3.70g O₂ => 8.25g CO₂ (actural yield)
(3.70g O₂)/(32g O₂/mol O₂)
= 0.1156 mol O₂ => 2(0.1156) mol CO₂
= 10.175g (Theoretical Yield)
%Yield = (Actual Yield / Theoretical Yield)100%
= (8.25g/10.175g)100% = 81% Yield
Answer:
c) H2O and OH−
Explanation:
Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.
When an acid donates a proton, it changes into a base which is known as its conjugate base.
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.
Thus, for the reaction,
The base is 
and the conjugate acid of the base is 
.
Also, The base is 
and the conjugate acid of the base is 
.
<u>Correct option is :- c) H2O and OH−</u>
I believe it was James Hutton
To determine the heat required in order to decompose a certain amount of a substance, we need information on the heat needed to decompose one mole of the substance. This value are readily available online and other sources. For this reaction, the heat needed is 129 kJ per 2 mol of NaHCO3. We calculate as follows:
129 KJ / 2 mol NaHCO3 (1 mol / 84.01 g ) (25.5 g NaHCO3 ) = 19.58 kJ of heat is needed.
