Step 1
Glucose enters glycolysis pathway and glycolysis yields pyruvate, then pyruvate undergoes processing.
step 2
Pyruvate processing ;releases acetylCOA which joins the citric acid cycle.
Step 3
The citric acid cycle yields 2ATP and CO2 and also releases NADH and FADH2 to electron transport chain and chemiosmosis.
Step 4
Chemiosmosis and electron transport chain yields 25 ATP molecules and H2O Oxygen enters electron transport chain and osmosis.
Answer:
1. 39 J; 2. 3.9 % usable; 3. 96.1 % unusable
Step-by-step explanation:
1. Available energy
Energy consumed = 1000 J
Less waste = - 177 J
Less respiration = <u>-784 J
</u>
Total energy lost = <u>-961 J
</u>
Available energy = 39 J
2. Percent of total energy usable
The chipmunk could use only 39 J of the original 1000 J.
% of energy usable = 39 J/1000 J × 100 % = 3.9 %
3. Percent of energy unusable
The chipmunk lost 961 J of the original 1000 J.
% of energy unusable = 961 J/1000 J × 100 % = 96.1 %
It is water soluble and therefore the substance is hydrophilic
Answer:
When one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and ATP is converted to adenosine diphosphate (ADP). Likewise, energy is also released when a phosphate is removed from ADP to form adenosine monophosphate (AMP).
Explanation:
