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monitta
3 years ago
7

A chemist is trying to classify an unknown substance as either a metal or nonmetal. What question should the chemist use to help

classify the material?
A. Does the material feel hard to the
touch?

B. Does the material feel rough or smooth?

C. Is the material a good conductor or a poor conductor?

D. Will the material float in water?


Please Help me!!!​
Chemistry
1 answer:
alekssr [168]3 years ago
8 0

Answer:

c

Explanation:

metals are good conductors, while non metals are not good conductors

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Answer:

True is the answer to this question

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A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}      ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL

Putting values in above equation, we get:

0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g

Hence, the mass of glucose in final solution is 1.085 grams

4 0
3 years ago
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tester [92]

Answer:

chemical change

Explanation:

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6. What is the equilibrium constant for the following reaction?<br> C+02 = CO2
Orlov [11]
<h3>\tt Kc=\dfrac{[CO_2]}{[C][O_2]}</h3><h3>Further explanation</h3>

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Reaction

C+02 = CO2

Required

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\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

So for the reaction :

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4 years ago
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