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kompoz [17]
3 years ago
5

How many moles of Co are needed to produce nine moles of CO2

Chemistry
2 answers:
ahrayia [7]3 years ago
7 0

Answer:

2. 8 moles of carbon dioxide can be produced from 12.5 moles of oxygen. 1 mole of octane can be produced from 8 moles of carbon dioxide gas.

Explanation:

hope this helps :)

inna [77]3 years ago
4 0

Answer:

guizzes

Explanation:

guizlet

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2 years ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
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7 0
3 years ago
Determine the molar mass of H2O2 (the solute) in a 1.5M aqueous solution of H2O2
Lera25 [3.4K]

Answer:

The molar mass of  H₂O₂ (the solute) in the aqueous solution of

H₂O₂ is 51 g

Explanation:

Given;

H₂O₂ compound

Concentration of aqueous solution of H₂O₂ = 1.5M

The molecular mass of H₂O₂ = (1 x 2) + (16 x 2) = 34 g/mol

Concentration(M) = \frac{Reacting \ mass \ (g)}{Molar \ mass \ (g/m)}

Reacting mass (g) = Concentration x Molar mass

Reacting mass (g) = 1.5 x 34

Reacting mass (g) = 51 g

Therefore, the molar mass of  H₂O₂ (the solute) in the aqueous solution of

H₂O₂ is 51 g

3 0
4 years ago
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