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xz_007 [3.2K]
3 years ago
6

Write In (4/9) in terms of In 2 and In 3.

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
Answer

A) 2 ln 2 - 2 ln 3

Explanation

Using the laws of logarithms:

ln (x/y) = ln (x) - ln (y)

ln (4/9) = ln (4) - ln (9)

This can be written as

ln (2^2) - ln (3^2)

Another law is:

ln (n^m) = m ln(n)

So finally:

2ln (2) - 2ln 3
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Step-by-step explanation:

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Let's calculate:

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Step-by-step explanation:

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3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

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so, the equivalent system is: 4x+4y=32 and x-y=2

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Problem 1 Answer:

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Problem 2:

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solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

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Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

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Answer:

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