A 4.70 g of a C.H. compound was combusted in air to make 15.3 g of CO, and 4.70 g H.O. What is the empirical formula? Balance th
1 answer:
Answer:
The empirical formula is C₂H₃
Explanation:
The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound.
The reaction of combustion for a CₐHₓ is:
CₐHₓ + (a+x/4) O₂ → a CO₂ + ˣ/₂ H₂O
The moles obtained are
15,3 g of CO₂ × = 0,3476 moles of CO₂≡moles of C
4,70 g of H₂O × = 0,2608 moles of H₂O × 2 = 0,5216 moles of H.
The ratio H:C is 0,5216/0,3476= 1,5. That means you have 1,5 H per 1C, that is the same than 3H per 2C. Thus, empirical formula is:
C₂H₃
I hope it helps!
You might be interested in
<h2>Input = 
, water and Output = 
</h2>
Explanation:
The light reactions of photosynthesis use water and produce Oxygen, NADPH.
The equation for photosynthesis :
→
The process of photosynthesis in two stages -
- The first stage is called the light reaction in which the light energy from the sun is captured and converted into chemical energy stored in the form of ATP and NADPH
- The second stage is the process of conversion of ATP molecules to sugar or glucose (the Calvin Cycle)
For a light reaction -
Net Input is of, ,
Net Output is of,
Al
Explanation:
The limiting reactant will be Al:
4Al + 3O₂ → 2Al₂O₃
The limiting reactant is the reactant in short supply in a chemical reaction.
Given parameters:
Mass of Al = 30g Molar mass = 27g/mol
Number of moles = =
Number of moles of Al = 1.111 mole
Mass of O₂ = 30g, molar mass = 32g/mol
Number of moles = = 0.94mol
In the reaction:
4 moles of Al reacted with 3 moles of O₂
1.11moles of Al will require = 0.83mole to react
But we have been given 0.94mole of O₂. This is more than required.
Therefore O₂ is in excess and Al is the limiting reactant.
Learn more:
Limiting reagents brainly.com/question/6078553
#learnwithBrainly