A solute dissolves in excess solvent to form a solution:
solute + solvent → solution
<h3>What is the Enthalpy and their relation ? </h3>
A thermodynamic system's enthalpy, which is one of its properties, is calculated by adding the system's internal energy to the product of its pressure and volume. It is a state function that is frequently employed in measurements of chemical, biological, and physical systems at constant pressure, which the sizable surrounding environment conveniently provides.
A solution is a uniform mixture of two or more components that can exist in the solid, liquid, or gas phases. The amount of heat that is released or absorbed during the dissolving process is known as the enthalpy change of solution (at constant pressure).
There are two possible values for this enthalpy of solution ( H solution ) : positive (endothermic) and negative (exothermic). It is most straightforward to visualize a hypothetical three-step process occurring between two substances while trying to grasp the enthalpy of solution. The solute is one substance; let's call it A. The solvent is the second component; let's call it B.
The initial procedure exclusively affects the solute A and calls for disabling all intramolecular forces holding it together. This indicates that the molecules of the solute separate. This process' enthalpy is known as H1. Since breaking interactions requires energy, this is always an endothermic process, hence H1>0.
Their sign will be opposite.
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Answer:
192.9
Explanation:
From the question,
Ke = [HCL]²/[H₂][CL₂].......................... Equation 1
Where Ke = Equilibrium constant.
Given: [HCL] = 0.0625 M, [H₂] = 0.0045 M, [CL₂] = 0.0045 M
Substitute these values into equation 1
Ke = (0.0625)²/(0.0045)(0.0045)
ke = (3.90625×10⁻³)/(2.025×10⁻⁵)
ke = 1.929×10²
ke = 192.9
Hence the equilibrium constant of the system = 192.9
When the amount of gas in a container is increased, the volume increases. Lussac's law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
Answer: B.
The rate of the nuclear reaction increases, but the rate of the chemical reaction remains the same
Explanation:
