I have no idea what the answer is

Which answer is the correct form of bar notation for this decimal number: 4.676767…

Rudiy27

Hello There!

Well all of your answer options are the same so i suppose they are all right.

Hope This Helps You!
Good Luck :)

4 0

3 years ago

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Identify the sequence graphed below and the average rate of change from n = 1 to n = 3. coordinate plane showing the point 2, 10

Katena32 [7]

Answer:

geometric sequence with initial value 20 and common ratio 1/2
average rate of change on [1, 3] = -7.5

Step-by-step explanation:

(a) The given points have sequential values of x and values of y that are each 1/2 the value before. The common ratio tells us the sequence is a geometric sequence.

(b) The first given point is (2, 10), so extrapolating backward, we determine the previous point to be ...

... (2-1, 10/(1/2)) = (1, 20)

Thus, we have enough information to determine the average slope between n=1 and n=3.

... (difference in y)/(difference in n) = (5 -20)/(3 -1) = -15/2 = -7.5

4 0

3 years ago

Which expressions are equivalent to the given sort 40 (there is more than one and the one selected is correct)

Basile [38]

Answer:

$40 {}^{ \frac{1}{2} }$

Step-by-step explanation:

The last one is also the answer

Using the rational exponet rule,

$\sqrt[n]{ {x}^{m} } = x {}^{ \frac{m}{n} }$

Using this number,

$\sqrt{40}$

40 is the base so it will stay same. Remember this is a square root sign so our nth root is 2 so our denominator if the rational exponet is 2.

$40 {}^{1} = 40$

so our numerator is 1 so

$40 {}^{ \frac{1}{2} }$

3 0

3 years ago

Gracie's grandmother gave her 40 stamps.

Advocard [28]

Answer:....................

Step-by-step explanation:

4 0

3 years ago

A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?

skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0

3 years ago

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