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Cerrena [4.2K]
4 years ago
11

Round 743214 to the nearest ten thousand

Mathematics
1 answer:
MrRa [10]4 years ago
4 0
The answer is 740,000. I hope this helps!
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What is 16344 times 8362 this is home work
Svetlanka [38]
136,668,528 is the answer I got I hope this helps
8 0
3 years ago
Read 2 more answers
2=(1+r/100n)^nt
klasskru [66]

Answer:

a) Log ( 2 ) = 4t Log ( 83/80 )

b) 4.7 years

Step-by-step explanation:

Attached below is the detailed solution

<u>a) exponential statement in log form for an investment at 15% quarterly </u>

Log ( 2 ) = 4t Log ( 83/80 )

n = 4 ,  r = 15

<u>b) using change to base  to find double time in yr </u>

Double time in yr

t = Log ( 2 ) / 4log ( 83/80 )

= 4.7 years

5 0
3 years ago
How do I do this????
Stolb23 [73]
At point B the object in motion is moving at a constant speed where at point A the movement is increasing (accelerating).
7 0
3 years ago
A student spent 15 minutes getting a 2-foot by 3-foot bulletin board. To the nearest tenth of a minute, how long did it take the
Cerrena [4.2K]

Answer:

The student took 2.5 minutes to paint 1 square foot.

Step-by-step explanation:

In order to know how long the student took to paint each square foot we first need to know the total area of the bulletin board. Since it is a rectangle we can compute it's area by multiplying the width and the height. That is:

area = 2*3 = 6 square foot

Since the student took 15 minutes to paint the whole board the pace at which he was working can be calculated by dividing the total area of the board by the time he took to paint all of it. So we have:

pace = 6/15 = 0.4 foot/min

To find how long it took him to paint 1 square foot we can divide it by the pace he was painting. We have:

time = 1/0.4 = 2.5 minutes

The student took 2.5 minutes to paint 1 square foot.

3 0
4 years ago
A) Find the average rate of change of the area of a circle with respect to its radius r as r changes from 4 to each of the follo
Black_prince [1.1K]
Area = π x radius²
dA/dr = 2πr
Average rate of change = (rate of change at one instant + rate of change at other instant)/2
= (2πr₁ + 2πr₂)/2
= (r₁ + r₂)π
Ai) 9π
Aii) 8.5π
Aiii) 8.1π

B) Instantaneous change:
(dA/dr) at (r = 4) = 2π(4)
= 8π
7 0
3 years ago
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