Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
He paid 3.19 per gallon both times......first time he bought 12.53 gallons....next time he bought 11.86 gallons
so ur expression is : 3.19(12.53 + 11.86)
Answer: a) 0.2222, b) 0.3292, c) 0.1111
Step-by-step explanation:
Since we have given that
Let the probability of getting head be p.
Since, its head is twice as likely to occur as its tail.
a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?
So, here, n = 3
Now,
b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?
2 tails means 3 heads.
So, it becomes,
c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?
Hence, a) 0.2222, b) 0.3292, c) 0.1111
