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erma4kov [3.2K]
3 years ago
9

What is the term that describes the amount of water in a volume of air at a specific temperature compared to the amount of water

that could be in the air at that temperature?
moisture

relative humidity

dew point

precipitation
Physics
2 answers:
Natasha_Volkova [10]3 years ago
6 0
I believe it is relative humidity.
morpeh [17]3 years ago
4 0

Answer:

relative humidity

Explanation:

We shall first examine the meanings of all terminologies and then deduct our  answer

Moisture : The presence of a liquid substances in the environment in form of vapor

Relative humidity : Is the amount of water vapor in the atmosphere. It determines  how dry or cool the air is.    High humidity means cool environment (air); Low humidity means  dry environment

Dew point : It is the atmospheric temperature below which condensation of water droplets begin and then dew is form

Precipitation: All forms of water particles, whether liquid or solid, that fall from the atmosphere for examples rain, hail, snow or sleet.

From the explanation above, we can deduce that the term that describes the amount of water in volume  of air at a specific temperature  compared to the amount of water that could be in the air at that temperature  is   relative humidity

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If two people are running at the same speed in the same direction. One person is one meter ahead of the other. The person in fro
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Answer:yes

Explanation:

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3 years ago
Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to
Debora [2.8K]

Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

<em>I will take two assumptions:</em>

The charge is homogeneous, so the density is constant all along the wire.

As we work with a linear charge density we work in one dimension, so the wire "has no radius"

Originally, the wire has a charge Q and a length L.

The linear charge density will be given by:

λ = Q/L

Now the length of the wire is stretched to 10 times the original length, so we have:

L' = 10*L

We want to find the value of Q' such that λ' (the <u>linear density of the stretched wire</u>) is still equal to λ.

Then we will have:

λ' = Q'/L' = Q'/(10*L) = λ = Q/L

Q'/(10*L) = Q/L

Q'/10 = Q

Q' = 10*Q

So the new <u>charge must be 10 times the original charge</u>, this means that we need to add 9*Q of charge to keep the linear charge density unchanged.

If you want to learn more, you can read:

brainly.com/question/14514975

6 0
3 years ago
16. If "team A has 3 of its bocce balls closer to the pallino than any of their opponent's balls, who wins the
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Answer:

Team A wins the frame with three points. The opposing team gets zero points for the frame.

Explanation:

7 0
3 years ago
A 14.0 gauge copper wire of diameter 1.628 mmmm carries a current of 12.0 mAmA . Part A What is the potential difference across
NARA [144]

Answer:

a) 2.063*10^-4

b) 1.75*10^-4

Explanation:

Given that: d= 1.628 mm = 1.628 x 10-3 I= 12 mA = 12.0 x 10-8 A The Cross-sectional area of the wire is:  

A=\frac{\pi }{4}d^{2}  \\=\frac{\pi }{4}*(1.628*10^-3 m)^2\\=2.082*10^-6 m^2\\

a) <em>The Potential difference across a 2.00 in length of a 14-gauge copper  </em>

<em>    wire: </em>

  L= 2.00 m

From Table  Copper Resistivity p= 1.72 x 10-8 S1 • m The Resistance of the Copper wire is:

R=\frac{pL}{A}

   =0.0165Ω

The Potential difference across the copper wire is:  

V=IR

 =2.063*10^-4

b) The Potential difference if the wire were made of Silver: From Table: Silver Resistivity p= 1.47 x 10-8 S1 • m

The Resistance of the Silver wire is:  

R=\frac{pL}{A}

   =0.014Ω

The Potential difference across the Silver wire is:  

V=IR

 =1.75*10^-4

4 0
3 years ago
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valkas [14]

Answer:

8,25 creo

Explanation:

nose no estoy segura

7 0
3 years ago
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