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Verizon [17]
3 years ago
14

What should the person do?

Chemistry
2 answers:
Katen [24]3 years ago
4 0
The answer: All of the above
hopes it helps :)
Nadusha1986 [10]3 years ago
4 0
All or the above sweet heart ❤️❤️
You might be interested in
Which reason explains why the boiling point of water (H2O) is higher than the boiling point of hydrogen sulfide(H2S)
FrozenT [24]
Covalent bonding because I remember from school
5 0
2 years ago
If an object has a volume of 5 mL and a mass of 50 g, what is the density of the object?
mr Goodwill [35]
Using the formula density = mass ÷ volume, I got my answer as 10g/cm^3 or 10g/mL
6 0
3 years ago
How do you determine the chemical reactivity for metals by using the periodic table?
vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

4 0
4 years ago
7. If one container holds 3.45 gallons of gas, how many containers would I need to hold 17
NNADVOKAT [17]

Answer:

5

Explanation:

if you do 17/3.45

=4.9 but if you round it up to the nearest whole number 5.

3.45*5=17.25

it equals to 17.25

7 0
3 years ago
at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a p
Alex

Answer:

initial temperature=-3.31^{\circ}C

Explanation:

Assuming that the given follows the ideal gas nature;

P_1=0.723atm

V_1=13.5L

T_1=?

P_2=0.612atm

V_2=17.8L

T_2=28 ^{\circ}C =273+28K=301K

mole of gass will remain same at any emperature:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

putting all the value we get:

T_2 =269.7K =-3.31 ^{\circ} C

initial temperature=-3.31^{\circ}C

6 0
3 years ago
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