a 20.5g sample of cleaning detergent contains 8.61g of NH40H.CALCULATE the percentage composition of nitrogen in the cleaning de
1 answer:
Answer:
The mass percentage composition of nitrogen in the sample of the cleaning detergent is approximately 16.78%
Explanation:
The given mass of the sample of the cleaning detergent, m₁ = 20.5 g
The mass of the ammonium hydroxide, NH₄OH in the detergent, m₂ = 8.61 g
The molar mass of NH₄OH = 35.04 g/mol
The molar mass of nitrogen, N = 14.01 g/mol
Therefore, the mass, m₃ of nitrogen, N, in 8.61 g of ammonium hydroxide, NH₄OH, is found as follows;
m₃ = (14.01/35.04) × 8.61 g = (402,087/118,800) g ≈ 3.44 g
The mass of nitrogen, N, in the ammonium hydroxide, NH₄OH, contained in the 20.5 g sample of the cleaning agent, m₃ ≈ 3.44 grams
The percentage composition of nitrogen in the sample of the cleaning detergent, %N is given as follows;
Therefore;
%N ≈ ((3.44 g)/(20.5 g)) × 100 ≈ 16.78 %
The percentage composition of nitrogen, %N ≈ 16.78%.
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Answer:
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Explanation:
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In this case, according to the given information, it turns possible for us to solve this problem by firstly considering that this reaction occurs between potassium iodide and lead (II) nitrate to yield potassium nitrate and lead (II) iodide which is clearly not balanced since we have one iodine atom on the reactants and two on the products, that is why the balance implies the placement of a coefficient of 2 in front of both KI and KNO3 as shown below:
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