Question

List the partial products of 42 x 28

Answer 1

Solution: The partial products of $42\times28$ are 800, 320, 40, 16 and the value of $42\times28$ is 1176.

Explanation:

To find the partial product of two numbers, first we write the both numbers as the sum of place values of the digits. Multiply each the place value of first number with the place value of second number.

$42\times28$

$(40+2)\times(20+8)$

$40\times 20+40\times 8+2\times 20+2\times 8$

Multiply each pair individually.

$40\times 20=800$

$40\times 8=320$

$2\times 20=40$

$2\times 8=16$

The above values are partial product.

$800+320+40+16=1176$

Therefore, the partial products of $42\times28$ are 800, 320, 40, 16 and the value of $42\times28$ is 1176.

Answer 2

42 × 48

(40 + 2) × (40 + 8)

40 × (40 + 2) = (40 × 40) + (40 × 2) = 1600 + 80 = 1680 
8 × (40 + 2) = (40 × 8) + (2 × 8) = 320 + 16 = 336

Then 1680 + 336 = 2016