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Nuetrik [128]
3 years ago
5

If a data point is way off the trend line which of the following will not help resolve the problem

Physics
1 answer:
S_A_V [24]3 years ago
3 0
Need more details to answer
You might be interested in
Select the correct answer.
kipiarov [429]

Answer:

A

Explanation:

If the object is moving at a constant speed, the object isn't accelerating as the velocity doesn't change.

5 0
3 years ago
A bedroom bureau with a mass of 45 kg, including drawers and clothing, rests on the floor. (a) If the coefficient of static fric
sergij07 [2.7K]

Answer: the minimal force that you need to apply to move the bureau is F = 198.45N

Explanation:

If you want to move an object, you need to apply a force that is bigger than the force of the statical friction.

The force of statical friction can be written as.

Ff = k*N

where k is the coefficient of static friction, in this case, k = 0.45, and N is the normal force between the object and the surface.

In this case, the normal force is the weight of the bedroom bureau, this is:

N = m*g = 45kg*9.8m/s^2 = 441N

Then the force is:

Fr = 0.45*441N = 198.45N

This means that the minimal force that you need to apply to move the bureau is F = 198.45N

and after this point, the force of friction will work wit the kinetic coefficient of friction, that usually is smaller than the statical one.

4 0
3 years ago
A force 80N accelerates a 5kg body .Find the acceleration if the coefficient of friction is 0.44
allochka39001 [22]

Answer:

Explanation:

20n

4 0
3 years ago
Which best describes the image of a concave mirror when
mr_godi [17]

Answer:

when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted

Explanation:

Let's use the constructor equation to describe the image of a concave mirror

    1 / f = 1 / p + 1q

where f is the focal length, p and q the distance to the object and the image, respectively

     1 /q = 1/f - 1/p

tell us that the image is between the focal and twice the focal, let's calculate the position of the image

for both ends

case 1, distance to the object       p = f

     

       1 / q = 1 / f -1 / f

       1 / q = 0

       q = ∞

    the image is in infinity

case2, distance to object p = 2f

     1 / q = 1 / f - 1 / 2f

     1 / q = 1 / 2f

     q = 2f

the image is twice the focal length, the object and the image are at the same point

therefore the image when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted

5 0
3 years ago
"Ryan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Ryan drove
Flura [38]

Answer:

Distance between Ryan home and mountain will be 252 miles

Explanation:

Let the distance from home to mountains is d

It is given that it took 7 hours to go mountains from home

Let the speed in going to mountain is v

Then according to question speed in coming from mountain is v+27

And time taken in come from mountain to home is hour

As distance will be same in both case

Distance will be equal to distance=speed\times time

So v\times 7=(v+27)\times 4

3v=108

v = 36 miles per hour

So distance will be equal to d=36\times 7=252miles

8 0
3 years ago
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