Answer:
Explanation:
Acceleration of cylinder
a = g sin 30 / 1+ k² / r² where k is radius of gyration and r is radius of cylinder.
For cylinder k² = (1 / 2) r²
acceleration
= gsin30 / 1.5
= g / 3
= 3.27
v² = u² + 2as
= 2 x 3.27 x 6
v = 6.26 m /s
v = angular velocity x radius
6.26 = angular velocity x .10
angular velocity = 62.6 rad / s
b ) vertical component of velocity
= 6.26 sin 30
= 3.13 m /s
h = ut + 1/2 g t²
5 = 3.13 t + .5 t²
.5 t²+ 3.13 t- 5 = 0
t = 1.32 s
horizontal distance covered
= 6.26 cos 30 x 1.32
= 7.15 m
Answer:
5 meters per second squared
Explanation:
We calculate the acceleration using the formula:
a = (vf - vi) / t
where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.
In our case:
a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2
Answer:
5.95 ml
Explanation:
Given info
P1=2.9 atm
V1=8.21 ml
P2=4 atm
From Boyle's law we know that p1v1=p2v2 where p and v are pressure and volume respectively. This is at a constant temperature. Making v2 the subject of formula then
V2=p1v1/p2
V2= 2.9*8.21/4=5.95 ml