Answer:
The cornea of an eye is avascular
Explanation:
The healing process in case of a cornea transplant is slow, because the cornea is of an eye is avascular, i.e., it does not contain blood vessels and in the absence of the blood vessels in the cornea tissue the nutrients and oxygen is not able to get delivered there.
Thus the immune system, without the blood vessels in the cornea is weak and hence healing takes time in case of cornea transplant.
Answer:
Explanation:
You need something that relates distance to what the gravitational pull is. You can set up a complex sort of proportion. What you need is a number that is comparable to 9.81 or you can just use the Gravitational Force formula with a 4 tier fraction.
Givens
x = the additional distance toward outer space above the radius of the earth.
G is the gravitational constant.
m1 = the person's mass (which does not change no matter where you are).
m2 = the earth's mass
F1 = 588 N
F2 = 300 N
Formula
Solution
G*m1*m2 all cancel. So what you get looks like this.
Cross Multiply
588 * 6400^2 = 300*(6400+x)^2 Now all you need do is solve for x.
x will be in km.
588*40960000 = 300 * (40960000 + 12800x + x^2)
1.2288*10^10 + 3840000x + 300x^2 = 2.408448*10^10
300x^2 + 3840000x + 1.2288*10^10 = 2.408448 * 10^10
Subtract 2.409448 * 10^10 from both sides.
300x^2 + 3840000x - 1,179648 * 10^10
Now use the quadratic formula
I'm guessing I should have converted this to meters because I'm getting ridiculous numbers. They are already large enough as you can see. The method is correct, even if the numbers are not.
Answer:
30 C
Explanation:
Given:
Current flowing in the circuit (I) = 50 A
Start-up time (t) = 0.60 s
Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:
Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.
Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,
Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.
Answer:
speed of water is 0.0007138m/s
Explanation:
From the law of conservation of mass
Rate of mass accumulation inside vessel = mass flow in - mass flow out
so, dm/dt = mass flow in - mass flow out
taking p as density
where,
q(in) is the volume flow rate coming in
Q = is the volume of liquid inside tank at any time
But,
dQ = Adh
where ,
A = area of liquid surface at time t
h = height from bottom at time t
A = πr²
r is the radius of liquid surface
Hence,
so, the speed of water surface at height h
where,
is 75.7 L/min = 0.0757m³/min
h = 1.5m
so,
v = 0.04283 /60
v = 0.0007138m/s
Hence, speed of water is 0.0007138m/s