1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Makovka662 [10]
3 years ago
15

If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The ra

dius of the earth is 6400km and the value of g on the earth surface is 9.8m/s2. please explain....​
Physics
1 answer:
harkovskaia [24]3 years ago
4 0

Answer:

Explanation:

You need something that relates distance to what the gravitational pull is. You can set up a complex sort of proportion. What you need is a number that is comparable to 9.81 or you can just use the Gravitational Force formula with a 4 tier fraction.

Givens

x = the additional distance toward outer space above the radius of the earth.

G is the gravitational constant.

m1 = the person's mass (which does not change no matter where you are).

m2 = the earth's mass

F1 = 588 N

F2 = 300 N

Formula

\frac{F1}{F2} = \frac{588 N}{300N}=\frac{\frac{Gm1*m2/}{6400^2} }{\frac{G*m1*m2}{(6400 + x)^2} }

Solution

G*m1*m2 all cancel. So what you get looks like this.

\frac{588}{300} = \frac{(6400 + x)^2}{6400^2}

Cross Multiply

588 * 6400^2 = 300*(6400+x)^2  Now all you need do is solve for x.

x will be in km.

588*40960000 = 300 * (40960000 + 12800x + x^2)

1.2288*10^10 + 3840000x + 300x^2  = 2.408448*10^10

300x^2 + 3840000x + 1.2288*10^10 = 2.408448 * 10^10  

Subtract 2.409448 * 10^10 from both sides.

300x^2 + 3840000x - 1,179648 * 10^10

Now use the quadratic formula

I'm guessing I should have converted this to meters because I'm getting ridiculous numbers. They are already large enough as you can see. The method is correct, even if the numbers are not.  

 

You might be interested in
At the equator earth rotates with a velocity of about 465 m/s.
Dafna1 [17]
The given velocity is 465 m/s.

Part a.
465 \,  \frac{m}{s} =(465 \times 10^{-3} \,  \frac{km}{s})*( 3600 \,  \frac{s}{h} ) = 1674 \,  \frac{km}{h}
Answer: 1674 km/h

Part b.
1674  \frac{km}{h} = (1674 \,  \frac{km}{h})*(24 \,  \frac{h}{day}  ) = 40176 \,  \frac{km}{day}
Answer: 40,176 km/day.

 
3 0
3 years ago
Read 2 more answers
What primary element of light helps the observer see three-dimensions?
elixir [45]
<span>Shading. When light hits an opaque surface some is absorbed, the rest is reflected, The reflected light is called shading. Reflection is not simple and varies with material. The surface’s structure defines the details of reflection. Variations produce anything from bright specular reflection</span>
7 0
3 years ago
Read 2 more answers
Linh builds a circuit from the diagram shown. Which bulb could Linh remove from the circuit to make all of the other bulbs stop
LenKa [72]

Answer:

4

Explanation:

In order for the current to continue flowing through the circuit (and for the bulbs to continue shining), there must be a closed path containing the battery where current can flow. Let's see the effect of removing each bulb on the circuit:

- 1: when removing bulb 1 only, the current can still flow through the path battery-bulb 3- bulb 4

- 2: when removing bulb 2 only, the current can still flow through the path battery-bulb 3- bulb 4

- 3: when removing bulb 3 only, the current can still flow through the path battery-bulb 1-bulb 2- bulb 4

- 4: when removing bulb 4 only, the current can no longer flow. In fact, there is no closed path that contains the battery now, so the current will not flow and all the bulbs will stop shining.

4 0
3 years ago
Read 2 more answers
A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?
iren2701 [21]

Answer:

K.E=29.403125J

Explanation:

From the question we are told that

Mass M=100

Height 50-20=30m

Generally the equation for velocity before impact is is is mathematically given by

v=\sqrt{2gh}

v=\sqrt{2*9.8*30}

v=24.25

Generally the equation for Kinetic Energy is is mathematically given by

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}*100*(24.25)^2\\

K.E=29403.125J

K.E=29.403125J

8 0
3 years ago
transmission electron microscopes that use high-energy electrons accelerated over a range from 40.0 to 100 kv are employed in ma
Gekata [30.6K]

The spatial limitations in Picometer for the given range of electrons would be around 50 picometers.

What is a transmission electron microscope?

A transmission electron microscope (TEM) is a type of microscope that uses a beam of high-energy electrons to produce detailed images of the structure of materials at the atomic or molecular scale. TEMs work by passing a focused beam of electrons through a thin sample and collecting the transmitted electrons on a fluorescent screen or an electronic detector. The interaction of the sample with the electrons results in the formation of an image that can be magnified and displayed on a computer monitor. TEMs are widely used in the fields of materials science, biology, and nanotechnology and can provide information about the structure, composition, and properties of materials with a high level and resolution.

According to the problem:

The spatial resolution of a transmission electron microscope (TEM) is determined by the size of the electron probe, which is directly related to the energy of the electrons. The higher the energy of the electrons is, the smaller the size of the probe is and the higher the spatial resolution.

At the lower end of the energy range of 40.0 kV, the spatial resolution of the TEM would be on the order of hundreds of nanometers. At the higher end of the range (100 kV), the spatial resolution would be on the order of tens of nanometers.

In general, TEMs with electron energy in the range of 40-100 kV are capable of resolving details down to around 50 picometers (pm). However, the actual spatial resolution will depend on various factors, such as the quality of the electron optics, the stability of the electron beam, and the sample preparation.

It's worth noting that TEMs with even higher electron energies (up to several hundred kV) are available, which can achieve spatial resolutions down to the sub-angstrom level (less than 0.1 pm). However, these instruments are much more expensive and complex to operate than TEMs with lower electron energies.

To know more about de broglie wavelength, visit:

brainly.com/question/17295250

#SPJ4

7 0
1 year ago
Other questions:
  • Your soccer team needs to add a new player midseason. Which of these people would most likely demonstrate good sportsmanship bas
    14·2 answers
  • Traveler A starts from rest at a constant acceleration of 6 m/s^2. Two seconds later, traveler B starts with an initial velocity
    15·1 answer
  • Which of the following is not found in living things? Which of the following is not found in living things?
    14·2 answers
  • Answer and mark you as brainliest <br> it's that easy
    7·2 answers
  • A spring scale can be used on
    10·2 answers
  • PLEASE HELP! AWARDING BRAINLIEST!
    6·2 answers
  • Compare the densities of two objects that have the same volume, but one feels heavier than the other.
    9·1 answer
  • A battery is used to power a flashlight. When the flashlight is in use, what type of energy is lost during energy transformation
    8·2 answers
  • A well labelled diagram of outdoor thermometer​
    5·1 answer
  • What is the net magnetic flux through any closed surface?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!