1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Makovka662 [10]
3 years ago
15

If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The ra

dius of the earth is 6400km and the value of g on the earth surface is 9.8m/s2. please explain....​
Physics
1 answer:
harkovskaia [24]3 years ago
4 0

Answer:

Explanation:

You need something that relates distance to what the gravitational pull is. You can set up a complex sort of proportion. What you need is a number that is comparable to 9.81 or you can just use the Gravitational Force formula with a 4 tier fraction.

Givens

x = the additional distance toward outer space above the radius of the earth.

G is the gravitational constant.

m1 = the person's mass (which does not change no matter where you are).

m2 = the earth's mass

F1 = 588 N

F2 = 300 N

Formula

\frac{F1}{F2} = \frac{588 N}{300N}=\frac{\frac{Gm1*m2/}{6400^2} }{\frac{G*m1*m2}{(6400 + x)^2} }

Solution

G*m1*m2 all cancel. So what you get looks like this.

\frac{588}{300} = \frac{(6400 + x)^2}{6400^2}

Cross Multiply

588 * 6400^2 = 300*(6400+x)^2  Now all you need do is solve for x.

x will be in km.

588*40960000 = 300 * (40960000 + 12800x + x^2)

1.2288*10^10 + 3840000x + 300x^2  = 2.408448*10^10

300x^2 + 3840000x + 1.2288*10^10 = 2.408448 * 10^10  

Subtract 2.409448 * 10^10 from both sides.

300x^2 + 3840000x - 1,179648 * 10^10

Now use the quadratic formula

I'm guessing I should have converted this to meters because I'm getting ridiculous numbers. They are already large enough as you can see. The method is correct, even if the numbers are not.  

 

You might be interested in
which of the following helps to explain why you can lift heavy objects more easily when they are in water
lara [203]

Buoyancy from water. Buoyancy is an upward force on an object immersed in a fluid (i.e., a liquid or a gas), enabling it to float or at least to appear lighter.

3 0
3 years ago
Elena (60.0 kg) and Madison (65.0 kg) are ice-skating at the Rockefeller ice rink in New Yok city. Their friend Tanner sees Elen
Bas_tet [7]

1. +72.0 kg m/s

The momentum of an object is given by:

p = mv

where

m is the mass of the object

v is its velocity

Taking "to the right" as positive direction, for Elena we have

m = 60.0 kg is the mass

v = +1.20 m/s is the velocity

So, Elena's momentum is

p_e=(60.0 kg)(+1.20 m/s)=+72.0 kg m/s

2. -162.5 kg m/s

Here Madison is moving in the opposite direction of Elena (to the left), so her velocity is

v = -2.50 m/s

while her mass is

m = 65.0 kg

Therefore, her momentum is

p_m= (65.0 kg)(-2.50 m/s)=-162.5 kg m/s

3. -90.5 kg m/s

The total momentum of Elena and Madison is equal to the algebraic sum of their momenta; taking into account the correct signs, we have:

p=p_e + p_m = +72.0 kg m/s - 162.5 kg m/s =-90.5 kg m/s

4. 0.72 m/s to the left

We can find the final speed of Elena and Madison by using the law of conservation of momentum. In fact, the final momentum must be equal to the initial momentum (before the collision).

The initial momentum is the one calculated at the previous step:

p_i = -90.5 kg m/s

while the final momentum (after the collision) is given by

p_f = (m_e + m_m) v

where

m_e is Elena's mass

m_m is Madison's mass

v is their final velocity

According to the law of conservation of momentum,

p_i = p_f\\p_i = (m_e + m_m) v

So we can find v:

v=\frac{p_i}{m_e + m_m}=\frac{-90.5 kg m/s}{60.0 kg+65.0 kg}=-0.72 m/s

and the direction is to the left, since the sign is negative.

8 0
3 years ago
If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?​
devlian [24]

Answer:

it will remain same because mass of the body is constant everywhere

4 0
2 years ago
In concave lenses a Distance object appears ​
JulsSmile [24]

Answer:

it appears to be farther away than it actually is, and therefore smaller then the object itself.

4 0
2 years ago
A transformer has a secondary voltage of 140 volts and a secondary current of 3.5 amps. if the primary current is 10 amps, what
Lynna [10]

For an ideal transformer power loss is assumed to be zero

i.e. the power in primary coil due to input voltage must be equal to power in secondary coil due to output voltage

this can be written in form of equation

V_1 i_1 = V_2 i_2

here we know that

V_2 = 140 volts

i_2 = 3.5 A

i_1 = 10 A{/tex]now we will use above equation[tex]140*3.5 = 10 * V_1

V_1 = 49 volts

So primary coil voltage is 49 Volts

7 0
3 years ago
Other questions:
  • Determine the specific heat of iron if 6.1 j of energy are needed to warm 1.50 g of iron from 20.0◦c to 29.0◦c?
    7·1 answer
  • Draw the lewis dot structure for the ion scn−. (carbon is the central atom.) how many lone pairs of electrons are in this struct
    15·1 answer
  • Josie sees lightning off in the distance. A few seconds later she hears thunder. What can Josie conclude?
    14·2 answers
  • A 1451 kg car is traveling at 48.0 km/h. Compared to 48.0 km/h, what would be the fraction of energy the car would have if it we
    14·2 answers
  • If a tree falls in the middle of the woods and nobody is around to hear it, does it make a sound?
    5·2 answers
  • Solutions to environmental problems ________.
    14·1 answer
  • Does the asteroid belt revolve around the sun?
    14·1 answer
  • What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?
    5·2 answers
  • A baseball weighing 0.5 kg falls from the sky. You hit it with a bat with a force of 50 N at an upward angle of 45°.
    10·1 answer
  • Create a Graph : Include numbers, axes, and order pairs
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!