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sertanlavr [38]
3 years ago
14

5. Solve each equation by systematic trial.

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Answer:

a) x = 260

b) g = 218

c) z = 30

d) h = 5

Step-by-step explanation:

a) x-68=192

Predict a number; let's say x = 225

225-68=192\\157=192

Too low; try with a higher number; let's say x = 270

270-68=192\\202=192

Too high, we're closer.

x = 260

260-68=192\\192=192

--------------------------------------------------------------------------------------

b) g+33=251

let's say g = 230

230+33=251\\263=251

Too high. Try g = 221

221+33=251\\254=251

We're almost there. Let's try with g = 218

218+33=251\\251=251

----------------------------------------------------------------------------------------

c) 3z-16=74

Let's try with z = 15

3(15)-16=74\\45-16=74\\29=74

Too low; try a higher number. z = 30

3(30)-16=74\\90-16=74\\74=74

--------------------------------------------------------------------------------------------

d) 15h+9=84

Let's try with h = 6

15(6)+9=84\\90+9=84\\99=84

Too high; let's try with h = 5

15(5)+9=84\\75+9=84\\84=84

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Additive inverse of 400
Goshia [24]

Given:

A number is 400.

To find:

The additive inverse of 400.

Solution:

We know that the sum of a number and its additive inverse is 0.

If "a" is number and "b" is its additive inverse, then

a+b=0

Let x be the additive inverse of 400. Then,

400+x=0

Subtract both sides by 400.

400+x-400=0-400

x=-400

Therefore, the additive inverse of 400 is -400.

7 0
3 years ago
1. Explain why n root a^n= |a| when n is even, but not when n is odd.
kogti [31]

Step-by-step explanation:

In the expression a^n, for integer values of n greater than 1, there are n factors. For example, a^2 = a * 2 (2 factors), a^3 = a * a * a (3 factors), etc.

For a non-negative value of a, a^n is non-negative for all values of n.

If a is negative, and n is even, then a^n is non-negative.

If a is negative, and n is odd, then a^n is negative.

|a| is non-negative for all values of a.

sqrt_n(a^n) is negative for negative a and odd n, but |a| is always non-negative, so sqrtn(a^n) cannot equal |a| for odd n.

8 0
3 years ago
Subtract 7 from 16 and then multiply by 4 which expression shows this calculation
Masteriza [31]

Answer:

7 - 16 = 9 x 4 = 36

Step-by-step explanation: 1 - 16 7 times. 9 + 9 + 9 + 9 = 36

5 0
3 years ago
I need help please ?!!!!!
adell [148]
The answer is option one
6 0
3 years ago
Sum of two numbers is 42 and their difference is 8 . Find the numbers ?​
worty [1.4K]

Answer:

25 and 17

Step-by-step explanation:

25+17=42

25-17=8

7 0
3 years ago
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