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Digiron [165]
3 years ago
10

What is the percentage by mass of silicon (si) in iron aluminum silicate (Fe3Al2(SiO4)3)?

Chemistry
2 answers:
Ilya [14]3 years ago
8 0

Answer:

16.93%.

Explanation:

  • If we have 1.0  mol of Fe₃Al₂(SiO₄)₃:

∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (no. of moles of Fe₃Al₂(SiO₄)₃)(the molecular mass of Fe₃Al₂(SiO₄)₃)

∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (1)(the molecular mass of Fe₃Al₂(SiO₄)₃) = (the molecular mass of Fe₃Al₂(SiO₄)₃).

∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = 3(atomic weight of Fe) + 2(atomic weight of Al) + 3(molecular weight of (SiO₄)₃) = 497.7474 g.

The mass of Si in 1.0 mole of Fe₃Al₂(SiO₄)₃ = 3(atomic mass of Si) = 3(28.0855 g/mol) = 84.2565 g.

∵ The mass % of Si = (the mass of Si)/(the mass of Fe₃Al₂(SiO₄)₃) = (84.2565 g)/(497.7474 g) = 16.93%.

lorasvet [3.4K]3 years ago
8 0

Answer:

16.7%

Explanation:

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