Answer:
They are all formed in acidic solution.
Explanation:
The diagram for hemiacetal, acetal and imine is shown in the diagram below and a star is placed on the three of them since they are all form in acidic solution.
From the diagram; reaction of methanol with propanal leads to formation of hemiacetal. From CH₃OH(methanol), one hydrogen attaches itself to the Oxygen double bond on the propanal to form a new hydroxyl group, the other methoxyl (-O-CH₃) from methanol attaches itself to other part of the propanal.
The further addition of methanol to Hemiacetal yields to Acetal.
Imines are formed by Mannich Reaction which is the reaction of propanal with amine group and which is followed by the dehydration with a Schiff base.
Given-
Hydrogen ion concentration pH = 0.008
Now,
we know that pH + pOH = 14
pOH = 14-0.008
pOH = 13.992
None of the above I believe it is what can form a tornado??
The second level has s and p orbitals, the s orbital holds two electrons and all three p orbitals also hold two each for a total of eight electrons in the second energy level.
Answer:
a) 7.0 moles of NH3
b) 61.2 g of NH3
c) 4.15 g of H2
d) 8.9 ×10^19 molecules
Explanation:
Equation of the reaction;
N2(g) + 3H2(g) ⇄NH3(g)
a)
If 3 moles of H2 yields 1 mole of NH3
21 moles of H2 will yield 21 × 1 /3 = 7.0 moles of NH3
b)
1 mole of N2 yields 17 g of NH3
3.6 moles of N2 yields 3.6 moles × 17 g of NH3 = 61.2 g of NH3
c)
If 6g of H2 produces 17 g of NH3
xg of H2 will produce 11.76 g of NH3
x= 6 × 11.76/17
x= 4.15 g of H2
d)
If 6g of hydrogen yields 6.02 × 10^23 molecules of NH3
8.86 × 10^-4g of H2 yields 8.86 × 10^-4g × 6.02 × 10^23 /6 = 8.9 ×10^19 molecules
