Answer:
Option C = 1.72 mol
Explanation:
Given data:
Mass of KF = 100 g
Moles of KF = ?
Solution:
First of all we have to calculate the molar mass of KF.
Molar mass of KF = 39.0983 g/mol + 18.998403 g/mol
Molar mass of KF = 58. 0967 g/mol
Formula:
Number of moles = mass/molar mass
Number of moles = 100 g/ 58.0967 g/mol
Number of moles = 1.72 mol
Answer:
The rows on the periodic table are called periods. All the elements in a period have valence electrons in the same shell. The number of valence electrons increases from left to right in the period. When the shell is full, a new row is started and the process repeats.
<h2>
I hope it helps plz let me know if it is right or wrong.</h2>
41.38 % Mg
55.17 % O
3.45 % H
Explanation:
What is the percent composition of magnesium hydroxide Mg(OH)₂?
To find the percent composition we follow the next algorithm.
First we calculate the molar mass of Mg(OH)₂:
molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2
molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole
Now we devise the next reasoning:
if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H
then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H
X = (100 × 24) / 58 = 41.38 % Mg
X = (100 × 32) / 58 = 55.17 % O
X = (100 × 2) / 58 = 3.45 % H
Learn more about:
percent composition
brainly.com/question/419592
#learnwithBrainly
Answer:
4.31 × 10²
Explanation:
Equation of the reaction;
⇌ 
The ICE Table is shown as follows:
⇌
Initial 3.10 2.50 0
Change - x -x + 2x
Equilibrium (3.10 - x) 0.0800 2x
From ;
We can see that 2.50 - x = 0.0800
So; we can solve for x;
x = 2.50 - 0.0800
x = 2.42
which = (3.10 -x) will be :
= 3.10 - 2.42
= 0.68
= 2x
= 2 (2.42)
= 4.84
![K_c = \frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
430.62
≅ 431
= 4.31 × 10²
