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2 years ago

I need help with Chemistry: Mole Conversion It must be answered in complete detail

Chemistry

1 answer:

Anni [7]2 years ago

8 0

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

$\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \: = Given \: moles \: . Avogadro \: number}}}}$

Putting the given value we obtain

$\sf \twoheadrightarrow \: Number \: of \: atoms \: = 0.30 \times 6.022 \times {10}^{ 23} \\ \\ \sf \twoheadrightarrow \: Number \: of \: atoms \: = \: 1.8066 \times {10}^{ 23} atoms$

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

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The p K a pKa of acetic acid is 4.76 . 4.76. The p K a pKa of trichloroacetic acid is 0.7 . 0.7. Calculate the equilibrium disso

Andrei [34K]

Answer:

Acetic acid Ka = 1.74 × 10⁻⁵

Trichloroacetic acid Ka = 2 × 10⁻¹

Explanation:

Let's consider the acid dissociation of acetic acid.

CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq)

The pKa of acetic acid is 4.76. The acid dissociation constant (Ka) is:

pKa = -log Ka

- pKa = log Ka

Ka = anti log (-pKa)

Ka = anti log (-4.76)

Ka = 1.74 × 10⁻⁵

Let's consider the acid dissociation of trichloroacetic acid.

CCl₃COOH(aq) ⇄ CCl₃COO⁻(aq) + H⁺(aq)

The pKa of trichloroacetic acid is 0.7. The acid dissociation constant (Ka) is:

pKa = -log Ka

- pKa = log Ka

Ka = anti log (-pKa)

Ka = anti log (-0.7)

Ka = 2 × 10⁻¹

3 0

3 years ago

help!! i tried answering these on my own and turning it into my teacher and she said they were all wrong , can somebody help me

Kobotan [32]

I don't know what your answers were but the more "stuff" there is the more energy it takes to freeze or boil it. Hope this could help

6 0

3 years ago

Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and

alisha [4.7K]

H₂O would be the limiting reactant.

Balanced chemical equation:

6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

No. of moles of H₂O = Given mass/ Molar mass

= 238 / 18 = 13.22 moles

Moles of H₂O = 13.22

According to the balanced chemical equation

6 moles of CO₂ react with 6 moles of H₂O

So the reactant that has less number of moles will be consumed first.

As the No. of moles of H₂O < No. of moles of CO₂

So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

Learn more about limiting reactant here brainly.com/question/14222359

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2 years ago

Help me asappp please

Basile [38]

Answer:

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Explanation:

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3 0

3 years ago

the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?

ioda

The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

<h3>Position of 18o-labeled methanol in the products</h3>

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

Learn more about methanol here: brainly.com/question/17048792
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8 0

2 years ago