Answer:
0.60 M
Explanation:
Given data:
Mass of MgS = 32.9 g
Volume of solution = 971 mL (0.971 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of MgS:
Number of moles = mass/molar mass
Number of moles = 32.9 g/ 56.38 g/mol
Number of moles = 0.58 mol
Molarity of solution:
M = 0.58 mol/ 0.971L
M = 0.60 M
Here we have to get the height of the column in meter, filled with liquid benzene which exerting pressure of 0.790 atm.
The height of the column will be 0.928 m.
We know the relation between pressure and height of a liquid placed in a column is: pressure (P) = Height (h) × density of the liquid (ρ) × gravitational constant (g).
Here the pressure (P) is 0.790 atm,
or [0.790 × (1.013 × 10⁶)] dyne/cm². [As 1 atm is equivalent to 1.013 × 10⁶ dyne/cm²]
Or, 8.002ₓ10⁵ dyne/cm².
density of benzene is given 0.879 g/cm³.
And gravitational constant (g) is 980 cm/sec².
On plugging the values we get:
8.002×10⁵ = h × 0.879 × 980
Or, h = 928.931 cm
Or, h = 9.28 m (As 1 m = 100 cm)
Thus the height will be 9.28 m.
2 stands for valency of ca ion
its +2
that it takes two electrons to complete its shell
3-Methylpentane is the IUPAC name for the substance.
whether in a continuous chain or a ring, the longest chain of carbons joined by a single bond serves as the basis for IUPAC nomenclature. According to a precise set of priorities, all deviations—whether they involve numerous bonds or atoms other than carbon and hydrogen—are denoted by prefixes or suffixes.
+3-Methylpentane is the IUPAC name for the substance in question. It has a lengthy chain of 5 carbon atoms, which gives it the prefix pent-, and a single bond is what gives it the postfix -ane (alkane). Given that the methyl group is present at the third carbon, it is 3-methylpentane.
Learn more about IUPAC Nomenclature here-
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