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3 years ago

if there was no air resistance, how would the rate of fall of a coffee filter compare to the rate of fall of a basketball?

1 answer:

5 0

If there were no air resistance ... like, if you were doing the experiment on the surface of the moon where there ISN'T any air ... and if you dropped a feather, a basketball, a coffee filter, a rock, a piece of kleenex, a balloon, a car, a hammer, a rose petal, a house, a computer, a bag of M&Ms, a watermelon, a mosquito, a block of ice, a gum wrapper, a shirt, a flag, a satellite dish, a golf ball, a school bus, a jumbo-jet airliner, a banana, a leaf of a tree, a trunk of a tree, an apple, a brick, an avocado, and a battleship ... all from the same height, and you let them all go at the same time, they would all fall together, side by side, all with the same speed and the same acceleration, and they would all hit the ground at the same time.

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Which vector has an x-component with a length of 4?

Masja [62]

Answer:ITS Y

Explanation:

6 0

4 years ago

An action force is 40 N to the right. The reaction force must be: A. 20 N left B. 40 N left C. 20 N right D. 40 N right

Sergeeva-Olga [200]

Answer:

The answer to your question is letter B.

Explanation:

To answer this question, we must remember the third law of motion of Newton that states that For every action, there is an equal and opposite reaction.

Then, if the action force is 40 N to the right, the reaction force must be 40 N to the left.

8 0

3 years ago

What is the position at 2 seconds?

Step2247 [10]

5

If you go over 2 on the time bar, and you look for the black dot above the 2 on the bottom time bar, it would go up to 5.

8 0

4 years ago

A circular rod has a radius of curvature R = 9.09 cm and a uniformly distributed positive charge Q = 6.49 pC and subtends an ang

Digiron [165]

Answer:

E = 1.19 N/C

Explanation:

Let's first determine the length of the arc which can be given as:

L= Rθ

where:

L = length of the arc

R = radius of curvature

θ = angle in radius

L = (9.09×10⁻²m)(2.59)

L = (0.0909)(2.59)

L = 0.235431 m

Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:

$E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}-sin(-\frac{\theta}{2})]$

$E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}+sin(\frac{\theta}{2})]$

$E= \frac{2\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}]$

Since $\lambda = \frac{Q}{L}$

where;

L = length

Q = charge

λ = density of the charge;

then substituting $\frac{Q}{L}$ for λ, we have :

$E= \frac{2(\frac{Q}{L})}{4 \pi E_oR}[sin\frac{\theta}{2}]$

$E= \frac{2Q[sin\frac{\theta}{2}]}{4 \pi E_oLR}$

substituting our given parameter; we have:

$E= \frac{2(6.26*10^{-12}C)[sin\frac{2.59rad}{2}]}{4 \pi (8.85*10^{-12}C^2/N.m^2)(0.235431)(0.0909)}$

E = 1.1889 N/C

E = 1.19 N/C

∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C

4 0

3 years ago

A student pushes a 40-N block across the floor for a distance of 10 m. How much work was applied to move the block? A. 4 J B. 40

damaskus [11]

Now for this problem, what is given is a 40 Newtons which would represent the force to be applied to the object, and a distance of 10 meters after the application of the said force. When these two combine, work is done. The unit for work is Joules and this is what we are looking for. The formula to get Joules or for work would be the force applied to the object multiplied by the distance that it travelled after the application of the force. It looks like this

work = force x distance
Joules = Newtons x meter

so let us substitute the variables to their corresponding places

Joules = 40 N x 10 m
Joules = 400 J

So the answer to this question would be C. 400 J

7 0

3 years ago

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