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Kisachek [45]
3 years ago
5

An action force is 40 N to the right. The reaction force must be: A. 20 N left B. 40 N left C. 20 N right D. 40 N right

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

The answer to your question is letter B.

Explanation:

To answer this question, we must remember the third law of motion of Newton that states that For every action, there is an equal and opposite reaction.

Then, if the action force is 40 N to the right, the reaction force must be 40 N to the left.

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Two parallel slits are illuminated by light composed of two wavelengths. Wavelength A is 564 nm and the other is wavelength B an
anygoal [31]

Answer:

423nm

Explanation:

To find the unknown wavelength you take into account the distance y to the maximum central fringe, for light fringes and dark fringes.

- for light fringes:

dsin\theta=m\lambda\\\\sin\theta\approx\theta=\frac{y}{D}\\\\y=\frac{m\lambda_1D}{d}

- for dark fringes:

y=\frac{m\lambda_2/2 D}{d}

The third-order bright fringe (m= 3) of wavelength A coincides with the fourth dark fringe (m=4) of the wavelength B. Hence you have that:

\frac{(3)\lambda_1D}{d}=\frac{(4)\lambda_2D}{d}\\\\\lambda_2=\frac{3}{4}\lambda_1=\frac{3}{4}(564nm)=423nm

hence, the wavelength B is 423nm

7 0
4 years ago
Read 2 more answers
A very long, straight wire carries a current of 19.0 A in the +k direction. An electron 1.9 cm from the center of the wire in th
Anestetic [448]

(a) 1.03\cdot 10^{-16} N, -k direction

First of all, let's find the magnetic field produced by the wire at the location of the electron:

B=\frac{\mu_0 I}{2 \pi r}

where

I = 19.0 A is the current in the wire

r = 1.9 cm = 0.019 m is the distance of the electron from the wire

Substituting,

B=\frac{(1.256\cdot 10^{-6})(19.0A)}{2 \pi (0.019 m)}=2\cdot 10^{-4} T

and the direction is +j direction (tangent to a circle around the wire)

Now we can find the force on the electron by using:

F=qvBsin \theta

where

q=1.6\cdot 10^{-19}C is the electron's charge

v=3.23\cdot 10^6 m/s is the electron speed

B=2\cdot 10^{-4} T is the magnetic field

\theta is the angle between the direction of v and B

In this case, the electron is travelling away from the wire, while the magnetic field lines (B) form circular paths around the wire: this means that v and B are perpendicular, so \theta=90^{\circ}, sin \theta=1. So, the force on the electron is

F=(1.6\cdot 10^{-19}C)(3.23\cdot 10^6 m/s)(2\cdot 10^{-4} T)(1)=1.03\cdot 10^{-16} N

The direction is given by the right hand rule:

- Index finger: direction of motion of the electron, +i direction (away from the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means -k direction (anti-parallel to the current in the wire)

(b) 1.03\cdot 10^{-16} N, +i direction

The calculation of the magnetic field and of the force on the electron are exactly identical as before. The only thing that changes this time is the direction of the force. In fact we have:

- Index finger: direction of motion of the electron, +k direction (parallel to the current in the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means +i direction (away from the wire)

(c) 0

In this case, the electron is moving tangent to a circle around the wire, in the +j direction. But this is exactly the same direction of the magnetic field: this means that v and B are parallel, so \theta=0, sin \theta=0, therefore the force on the electron is zero.

6 0
3 years ago
What is another name for a business name or manufacture 's name
jenyasd209 [6]

Answer:

Company name

Corporation name

8 0
3 years ago
Read 2 more answers
What is equivalent resistance? How do you calculate it for a series circuit?
Annette [7]

FORMULA:

R(s) = R1 + R2 + R3 + Rn where n is the number of resistors.

ANSWER:

The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated.

We already know that, In series combination all the resistors are connected directly. So, to calculate the equivalent resistance in series we just have to add the all value of resistance.

8 0
3 years ago
The nose of an ultra-light plane is pointed is pointed South and its airspeed indicator shows 35m/s. The plane is in a 10m/s win
alex41 [277]

Answer:

v=42.66\ m.s^{-1}

\beta=6.75^{\circ} clockwise from the south.

Explanation:

Given:

  • velocity of the plane southwards, v_p=35\ m.s^{-1}
  • velocity of the wind in south-west, v_w=10\ m.s^{-1}
  • ∴Angle between the plane and wind velocities, \theta=45^{\circ}

<u>According to the vector addition rule, magnitude of the resultant velocity is given as:</u>

v=\sqrt{v_p^2+v_w^2+2\times v_p.v_w\ cos\ \theta}

v=\sqrt{35^2+10^2+2\times 35\times 10\ cos\ \45}

v=42.66\ m.s^{-1} is the plane's speed with respect to ground.

Direction of this resultant with respect to south:

tan\ \beta=\frac{v_w\ sin\theta}{(v_p+v_p\ cos\theta)}

tan\ \beta=\frac{10\ sin\ 45}{(35+35\ cos\ 45)}

\beta=6.75^{\circ} clockwise from the south.

8 0
3 years ago
Read 2 more answers
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