The temperature that the aluminum will have a resistivity that is three times the resistivity copper has at room temperature is 227°C.
<h3>How to calculate the temperature?</h3>
It should be noted that the temperature of resistivity is given as:
p(t) = p(20°C) (1 + (t - 20°C)
The resistivity at room temperature is illustrated as:
pCu(20°C) = 1.68 × 10^-8
pAl(20°C) = 2.65 × 10^-8
Therefore, the equation will be:
3 × 1.68 × 10^-8 = 2.65 × 10^-8(1 + 0.00435(t - 20°C)
0.902 = 0.00435(t - 20°C)
t = 20 + 207
t = 227°C
Therefore, the temperature is 227°C.
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