Force vectors, use Pythagoras to get resultant force: sqrt ((30^2 + (40^2)) = 50m/s
Answer:
Q=mc∆tita.
4780J= m × 2445J/kg/°C × 5.43°C
4780J= m× 13276.35J/kg
m= 0.36Kg
Answer:
B. Gravitational force
Explanation:
The gravitational force of an object (also called weight) is given by

where m is the mass of the object and g is the acceleration of gravity, and it always points in the downward direction.
In this problem, the arrow labelled with 4 is the only force pointing downward: therefore, it must be the gravitational force.
The other arrows represent:
1 --> component of the gravitational force parallel to the plane
2 --> force of friction
3 --> component of the gravitational force perpendicular to the plane
Answer:
y = 0m
y0 = 166m
v0y = 0 m/s
g = 9.8 m/s^2
t = ?
Solve for t:
y = y0 + v0y*t - (0.5)gt^2
0 = 166 - (0.5)(9.8)t^2
t = 5.82 s
Now, using time, we can solve for the range using the equation:
x = vx(t)
x = (40)(5.82)
x = 232.8 m
The impact horizontal component of velocity will be 40 m/s as velocity in terms of x is always constant. To find the impact vertical component of velocity, we use the equation:
v = v0y - gt
v = 0 - (9.8)(5.82)
v = -57.04 m/s