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Brums [2.3K]
3 years ago
6

Americium-241 is a radioactive isotope and a vital component of smoke detectors. what is the elemental identity of the decay pro

duct of americium-241 after it undergoes alpha decay?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
5 0
_{95}^{241}Am ---\ \textgreater \    _{2}^{4}He + ^{237}_{93}Np

During  \alpha- decay ,  \alpha - particle

 will be removed (_{2}^{4}He).

So mass number will decrease by 4, 

and atomic number will decrease by 2.

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Which of the following elements would be classified as a nonmetal? sulfur aluminum silicon calcium
Ahat [919]
Sulfur is a non metal 
7 0
3 years ago
Read 2 more answers
Rank the boiling points of the following molecules from highest to lowest. butanone diethyl ether butane and butanol.
Gekata [30.6K]

Answer:

From highest to lowest:

butanol: 117.7 degree Celsius

butanone: 79.64 degree Celsius

diethyl ether: 34.6 degree Celsius

n-butane: -0.4 degree Celsius

7 0
3 years ago
Fe2O3(s) + 3CO(g) ---> 2Fe(l) + 3CO2(g) Steve inserts 450. g of iron(III) oxide and 260. g of carbon monoxide into the blast
baherus [9]

Answer: Theoretical yield is 313.6 g and the percent yield is, 91.8%

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe_2O_3=\frac{450}{160}=2.8moles

\text{Moles of} CO=\frac{260}{28}=9.3moles

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(l)+3CO_2(g)

According to stoichiometry :

1 mole of Fe_2O_3 require 3 moles of CO

Thus 2.8 moles of Fe_2O_3 will require=\frac{3}{1}\times 2.8=8.4moles  of CO

Thus Fe_2O_3 is the limiting reagent as it limits the formation of product and CO is the excess reagent.

As 1 mole of Fe_2O_3 give = 2 moles of Fe

Thus 2.8 moles of Fe_2O_3 give =\frac{2}{1}\times 2.8=5.6moles of Fe

Mass of Fe=moles\times {\text {Molar mass}}=2.6moles\times 56g/mol=313.6g

Theoretical yield of liquid iron = 313.6 g

Experimental yield = 288 g

Now we have to calculate the percent yield

\%\text{ yield}=\frac{\text{Actual yield }}{\text{Theoretical yield}}\times 100=\frac{288g}{313.6g}\times 100=91.8\%

Therefore, the percent yield is, 91.8%

6 0
4 years ago
How many kilojoules of heat are released when 32.0 g of NaOH are dissolved in water? (The molar heat of solution of NaOH is –445
Katen [24]
The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
The number of NaOH moles in 32.0 g - 32.0 g / 40 g/mol =  0.8 mol
the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ
6 0
3 years ago
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Differentiate between acids and bases on the basis of their pH values Give an example of each type. Please help worth 100 points
gtnhenbr [62]

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Explanation:

3 0
2 years ago
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