IMA = Ideal Mechanical Advantage
First class lever = > F1 * x2 = F2 * x1
Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2
=> F1/F2 = x1 /x2
IMA = F1/F2 = x1/x2
Now you can see the effects of changing F1, F2, x1 and x2.
If you decrease the lengt X1 between the applied effort (F1) and the pivot, IMA decreases.
If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.
If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.
If you decrease the applied effort (F1) and decrease the distance between it and the pivot (X1) IMA will decrease.
Answer: Increase the length between the applied effort and the pivot.
Answer:
- 273.77 rad/s^2
Explanation:
fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps
f = 0
ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s
ω = 2 π f = 0
θ = 46 revolutions = 46 x 2π radian = 288.88 radian
Let α be the angular acceleration of the centrifuge
Use third equation of motion for rotational motion


α = - 273.77 rad/s^2
The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.
- Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.
F = G (M₁M₂)/r²
Where, F the gravitational force
G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant
M₁=5.98×10²⁴kg mass of earth
M₂= 1.99×10³⁰ kg the mass of the sun
r =15×10¹⁰ m is the distance between sun and earth
Putting all the values in above equation,
F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m
On solving the above equation we get,
F = 3.48×10²²N
To know more about gravitational force
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Answer:
Angular displacement before it stops = 18 rev
Explanation:
Given:
Speed of fan w(i) = 6 rev/s
Speed of fan (Slow) ∝ = 1 rev/s
Final speed of fan w(f) = 0 rev/s
Find:
Angular displacement before it stops
Computation:
w(f)² = w(i) + 2∝θ
0² = 6² + 2(1)θ
0 = 36 + 2θ
2θ = -36
Angular displacement before it stops = -36 / 2
θ = -18
Angular displacement before it stops = 18 rev