initial angular speed is given as 20 rev/second
so it is given as
now it comes to rest after 80 s
now we can use kinematics to find angular deceleration
so angular deceleration is 1.57 rad/s^2
Answer:
Explanation:
Let the slide be at a distance of u from lens . So the object distance is u.
Image distance v = 13 - u .
Using lens formula
1/v -1/u = 1/f
1/ ( 13 - u) - 1 / u = 1 / 2.33
u - (13 - u )/u(13 -u ) = 1/2.33
2u - 13/ 13u - u² = 1/ 2.33
4.66 u - 30.29 = 13 u -u²
u² - 8.34 u - 30.29 = 0
u = -2.73 cm
So lens will be at a distance of 2.73 cm from the slide.
A model train traveling at a constant speed around a circular track has a constant velocity. FALSE.
Hope this helps you!
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Answer:
<em>1.07m/s²</em>
Explanation:
From the question we are given the following
applied force Fapp = 450N
mass of the safe m = 100kg
Weight of the safe W = 980N
coefficient of kinetic friction n = 0.35
Required
Acceleration of the safe
According to Newton's second law
\sum Fx = ma
Fapp - Ff = ma
Ff is the frictional force
Fapp - nmg = ma
450 - 0.35(100)(9.8) = 100a
450 - 343= 100a
107 = 100a
a = 107/100
a = 1.07m/s²
<em>Hence the acceleration of the safe is 1.07m/s²</em>