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A typical current in a lightning bolt is 103 a. estimate the magnetic field 9 m from the bolt (in t). (enter the magnitude.)

kifflom [539]

The magnetic field is

$2.288 \times 10 {}^{ - 6} T$

what is magnetic field?

Magnetic field is defined as the relationship between the permittivity of free space,the magnitude of electric current,and distance.

Here is the formula,

$B = \frac{µ0l }{2π R}$

here,

B= magnitude of the magnetic field

l= magnitude of electric current

R=distance

µ0=permittivity of free space

Now,using above formula we can calculate the magnetic field

$B = \frac{µ0l }{2π R}$

$\frac{4\pi \times 10 {}^{ - 7}. \frac{m}{a} \times 103 }{2\pi \times (9m)}$

$= 2.288 \times 10 {}^{ - 6} T$

Thus,the magnetic field is

$= 2.288 \times 10 {}^{ - 6} T$

learn more about magnetic field from here: brainly.com/question/28326849

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4 0

2 years ago

When released , what is the kinetic energy of the 1c charge of the preceding problem if it flies past its starting position?

Alekssandra [29.7K]

A) When a charge is moved in an electric field the work done (W) is calculated as charge*(change in potential). We can write W = q*V or V = W/q = 10/1 = 10V . This voltage is a difference in electric potential between 2 points within the field. If the charge is positive, and positive work is done upon it, then the final position is more positive than the original one.

<span>b) If a charge (Q) is released from rest and falls through a potential difference V, then its gain in energy (KE if no other force acts on the charged body) is q*V = 10J. This is the same as the work done in moving the charge to its new position in part (a), and is an example of the conservation of energy.</span>

5 0

3 years ago

Particle q1 has a positive 6 µc charge. particle q2 has a positive 2 µc charge. they are located 0.1 meters apart. recall that k

Dmitrij [34]

(a) Force between the two charges

The electrostatic force between the two charges is given by:

$F=k\frac{q_1 q_2}{r^2}$

where k is the Coulomb's constant, q1 and q2 the two charges, r their separation.

In this problem:

$q_1 =6 \mu C=6 \cdot 10^{-6}C$

$q_2=2 \mu C=2 \cdot 10^{-6}C$

$r=0.1 m$

Substituting into the equation, we find

$F=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(6 \cdot 10^{-6}C)(2 \cdot 10^{-6}C)}{(0.1 m)^2}=10.8 N$

(b) direction of particle q2

Particle q2 wants to move in the direction of the force acting on it. The direction of the force depends on the relative sign of the two charges: like charges attract each other, opposite charges repel each other. In this case, the two charges are both positive, so they repel each other and q2 tends to move away from particle q1.

7 0

3 years ago

Read 2 more answers

John F. Kennedy was the youngest man ever to be elected President of the United States.

Furkat [3]

False. Theodore Roosevelt was the youngest.

5 0

3 years ago

An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?

seraphim [82]

Volume=mass/density

volume=455.6/19.3

volume=23.6 mL

4 0

3 years ago