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3 years ago

Can the volume of a gas be measured?

Physics

1 answer:

Scilla [17]3 years ago

5 0

Answer:

C. Just measure the volume of the container it is in

Explanation:

Another why of measuring the volume of gas is by filling a contractor with water then in invert a glass jar air will miss place the space taken by water then measure the volume of water misplaced to get the volume to air

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A pilot who accelerates at more than 4 g begins to "gray out" but doesn’t completely lose consciousness. (a) Assuming constant a

Allushta [10]

Answer:

33.7410805301 s

22336.5953109 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = $4\times 331$

s = Displacement

a = Acceleration = $4g=4\times 9.81\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{4\times 331-0}{4\times 9.81}\\\Rightarrow t=33.7410805301\ s$

The time taken is 33.7410805301 s

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 9.81\times 33.7410805301^2\\\Rightarrow s=22336.5953109\ m$

The plane would travel 22336.5953109 m

7 0

4 years ago

A 220 g mass is on a frictionless horizontal surface at the end of a spring that has force constant of 7.0

Talja [164]

The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:

x = 0.135 cm

Given parameters

The mass m = 220 g = 0.220 kg

The spring cosntnate3 k = 7.0 N / m

Initial displacement A = 5.2 cm = 5.2 10-2 m

To find

The position where the kinetic and potential energy are equal

A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.

x = A cos wt + fi

w² = $\frac{k}{m}$

Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.

The speed is defined by the variation of the position with respect to time.

v = $\frac{dx}{dt}$

let's evaluate

v = - A w sin (wt + Ф)

Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.

0 = - A w sin Ф

For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero

x = A cos wt

Let's find the point where the kinetic and potential energy are equal.

K = U

½ m v² = m g x

we substitute

½ A² w² sin² wt = g A cos wt

sin² wt = $\frac{2g}{A}$ cos wt

let's calculate

w = $\sqrt{\frac{7}{0.220} }$

w = 5.64 rad / s

sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

sin² 5.64t = 376.92 cos 5.64 t

1 - cos² 5.64t = 376.92 cos 5.64t

cos² 5.64t -376.92 cos564t -1 = 0

we make the change of variable

x = cos 5.64t

x²- 376.92 x - 1 = 0

x = 0.026

cos 5.64t = 0.026

Let's find the displacement for this time

x = 5.2 10-2 0.026

x = 1.35 10-3 m

In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

x = 0.135 cm

Learn more here: brainly.com/question/15707891

8 0

3 years ago

State any two precautions taken to ensure accurate result on simple pendulum<br>

galben [10]

Explanation:

1) The bob of pendulum should be displaced with a small angle. 2) The amplitude of the oscillation of a simple pendulum should be small. 3) Fans should be switched off to reduce the air resistance. 4)The simple pendulum should be oscillate in a vertical plane only.Feb 23, 2019

6 0

3 years ago

Determine la resistencia equivalente de la "escalera" de

defon

Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

$R_{t} = 341.7 \: \Omega$

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

Correspondiente a R8 y R9 es 0.23 A
Correspondiente a R7 es 0.17 A.

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

$R' = R_{1} + R_{2} + R_{3}$

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.

Entonces:

$R' = 3R$

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

$\frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}}$

$R'' = \frac{3}{4}R$

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

$R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R$

Esta resistencia está ahora en paralelo con R₇, entonces:

$\frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}}$

$R'''' = \frac{11}{15}R$

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

$R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega$

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

$V-i_{1}R-i_{3}R=0$ (1)

Malla 2

$-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0$ (2)

Malla 3

$-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0$ (3)

Recordemos tambien que:

$i_{1}=i_{2}+i_{3}$ (4)

$i_{2}=i_{4}+i_{5}$ (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

$i_{1}=3/13\: A$