You want to draw a free body diagram of the forces on the sled in the horizontal x-direction.
If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.
The angle made with the x-axis is cosine of the angle theta.
Please see picture attached.
This is honestly not something I’ve learned. The answer is something I don’t know.
Answer:
ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74
Explanation:
Answer:
The detailed calculations are shown below;
Explanation:
a)The maximum acceleration of the particle:
It is seen that the maximum change in velocity is at the time between 8s to 10s.
Maximum acceleration: 
= 
= 10 m/
b) The deceleration of the particle
The velocity of particle is decreased after 10s so,
deceleration = - 
= - 6.67 m/
c)The total distance traveled by the particle = Area under the curve
= 
* 4*20 + 4*20 + * 2*20+ 2*20+ * 40*16
= 290 m
d)The average velocity of the particle = 
= 
= 18.12 m/s
Answer:
Positive z direction.
Explanation:
The magnetic force acting on the electron is given by the formula as :
q is the charge on proton
v is the speed of proton
B is the magnetic field
It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,
q = +e
v = vi
B = Bj
Since, 
So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".
