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raketka [301]
3 years ago
8

PLEASE HELP!!! WILL MARK THE BRAINLIEST! HIGH SCHOOL PHYSICAL SCIENCE List the independent, dependent, controlled variables of t

he experiment.
Materials:
- hot plate
- thermometer
- scale
- measuring spoon
- water
- beakers
Physics
2 answers:
podryga [215]3 years ago
8 0

Answer:

Controlled variables are hot plate and measuring spoon

Dependant variables are scale and thermometer

Independant variables are beakers and water

Explanation:I tried my best, this should be right

serious [3.7K]3 years ago
3 0

Answer:

Explanation:

You didn't last any of the variables. You have to list the variables to tell which are which.

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Answer: 3.7 \times 10^{-4} N

Explanation:

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F = G\frac{Mm}{r^2}

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We have to calculate the net force on Earth due to Venus, Jupiter and Saturn when they are in one line. It means when they are the closest distance.

F_{net] = G\frac{M_eM_v}{r_v^2}+G\frac{M_eM_j}{r_j^2}+G\frac{M_eM_s}{r_s^2}

Mass of Earth, Me = 5.98 × 10²⁴ kg

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Mass of Jupiter, Mj = 318 Me

Mass of Saturn, Ms = 95.1 Me

closest distance between Earth and Venus, rv = 38 × 10⁶ km = 0.25 AU

closest distance between Jupiter and Earth, rj = 588 × 10⁶ km = 3.93 AU

closest distance between Earth and Saturn, rs = 1.2 × 10⁹ km = 8.0 AU

where 1 AU = 1.5 × 10¹¹ m

Inserting the values:

F_{net} = G\frac{M_e\times 0.815 M_e}{(0.25AU)^2}+G\frac{M_e\times 318 M_e}{(3.93AU)^2}+G\frac{M_e\times 95.1 M_e}{(8.0AU)^2}\\ \Rightarrow F_{net} = \frac{(GM_e^2)}{(1AU)^2}(\frac{0.815}{0.25^2}+\frac{318}{3.93^2}+\frac{95.1}{8.0^2})=\frac{6.67\times 10^{-11} \times (5.98\times 10^{24})^2}{(1.5\times 10^{11})^2}(35.1) = 3.7 \times 10^{-4} N

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