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Reil [10]
3 years ago
15

A class contributed $8.40 in dimes and quarters to the red cross. in all, there was 45 coins. how many coins of each kind were t

here?
Mathematics
1 answer:
rewona [7]3 years ago
5 0
A dime is a ten cent coin while a quarter is a 25 cent coin. The total of the money should be $8.40. Let x be the number of dime and y be the number of quarter. The equation that would best represent the given problem is,
                                  0.1x + 0.25y = 8.40
                                      x + y = 45
The values of x and y are 19 and 26, respectively. Thus, there are 19 dimes and 26 quarters. 
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7 0
3 years ago
Please answer and put how
muminat
6 + m/4 = 3 (subtract 6 from both sides)
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m = -12

Can plug in to original equation to check work:
6 - 12/4 = 3
6 - 3 = 3
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The answer m = -12 checks out
3 0
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