Answer:
The distance d from the car at which the sound from the stereo can still be discerned = 97720.5 m
Explanation:
Sound intensity heard at distance is related to the distance with the relation = (power of sound at the source)/(surface area of the wall of an imaginary sphere at the distance in question)
I = P/4πd²
Assuming the car has 2 speakers,
P = 0.06 W × 2 = 0.12 W
d = ?
For the intensity of the least discernible sound,
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
When conducting and experiment you want to have a notebook and something to write down notes with so you can keep everything organized and proper, and to not miss anything in the experiment. Also you want to have everything in order of the way it should be in.
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Answer:
-Increase in temperature: increase
-Decrease in temperature: decrease
-Increase in volume: increase
-Decrease in volume: decrease
-Increase in pressure: increase
-Decrease in pressure: decrease
Explanation:
-Increase in temperature:
● Molecules gain kinetic energy and move fast thus increasing distance
-Decrease in temperature:
● Kinetic energy of molecules decrease so they have smaller distance
-Increase in volume:
● Molecules have more space to move around so distance increase
-Decrease in volume:
● Less space, molecules collide with each other because of decreased distance thus increasing pressure
-Increase in pressure
● Molecules collide with each other and the walls of container increasing pressure so molecules move faster and it increases distance
-Decrease in pressure:
● Molecules collide with each other and walls of container less frequently so distance between molecules decrease
Explanation:
Given that,
Initial volume = 60dm³
Initial pressure = 30 kPa
We need to find the new volume when pressure changes to 40 kPa (say).
We know that the mathematical relation between volume and pressure is given by :
Put all the values,
So, when pressure of the gas increases, its volume get decreased.
