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Alex Ar [27]
3 years ago
9

Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single sto

ry building at the same instant of time. The time it takes the balls to reach the ground below will be:
a.about half as long for the heavier ball as for the lighter one.
b.about half as long for the lighter ball as for the heavier one.
c,about the same for both balls.
d.considerably less for the heavier ball, but not necessarily half as long.
e..considerably less for the lighter ball, but not necessarily half as long.
Physics
1 answer:
Gekata [30.6K]3 years ago
6 0

Answer:

c, About the same for both balls.

Explanation:

If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height.

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The example of the center of the gravity is the middle of a seesaw

Explanation:

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Which of these words describes humans
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Human are eurkaryotic.  Eukaryotes are organisms that have cells with a nucleus.  Prokayotes are cells without a nucleus.  Protists are eukaryotic but they are usually single cellular. Also, human are not fungus.  Fungus cannot move and have to get food from its surrounding area.
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3 years ago
We start with 5.00 moles of an ideal monatomic gas with an initial temperature of 128 ∘C. The gas expands and, in the process, a
o-na [289]

Answer:

The final temperature of the gas is <em>114.53°C</em>.

Explanation:

Firstly, we calculate the change in internal energy, ΔU from the first law of thermodynamics:

ΔU=Q - W

ΔU = 1180 J - 2020 J = -840 J

Secondly, from the ideal gas law, we calculate the final temperature of the gas, using the change in internal energy:

ΔU=\frac{3}{2} nRΔT

ΔU=\frac{3}{2} nR(T_{2} -T_{1} )

Then we make the final temperature, T₂, subject of the formula:

T_{2} =\frac{2ΔU}{3nR} +T_{1}

T_{2} =\frac{2(-840J)}{(3)(5)(8.314J/mol.K)} +128 deg.C

T_{2} =114.53 deg.C

Therefore the final temperature of the gas, T₂, is 114.53°C.

7 0
3 years ago
Work is always done when
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2 years ago
In 1977 off the coast of Australia, the fastest speed by a vessel on the water
fenix001 [56]

Answer: 154.08 m/s

Explanation:

Average acceleration a_{ave} is the variation of velocity  \Delta V over a specified period of time  \Delta t:

a_{ave}=\frac{\Delta V}{\Delta t}}

Where:

a_{ave}=1.80 m/s^{2}

\Delta V=V_{f}-V_{o} being V_{o}=0 the initial velocity and V_{f} the final velocity

\Delta t=85.6 s

Then:

a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}}

Since V_{o}=0:

a_{ave}=\frac{V_{f}}{\Delta t}}

Finding V_{f}:

V_{f}=a_{ave} \Delta t

V_{f}=(1.80 m/s^{2})(85.6 s)

Finally:

V_{f}=154.08 m/s

8 0
3 years ago
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