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Alex Ar [27]
3 years ago
9

Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single sto

ry building at the same instant of time. The time it takes the balls to reach the ground below will be:
a.about half as long for the heavier ball as for the lighter one.
b.about half as long for the lighter ball as for the heavier one.
c,about the same for both balls.
d.considerably less for the heavier ball, but not necessarily half as long.
e..considerably less for the lighter ball, but not necessarily half as long.
Physics
1 answer:
Gekata [30.6K]3 years ago
6 0

Answer:

c, About the same for both balls.

Explanation:

If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height.

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Answer:

You will discover that at high altitude, there is cold and the opposite is experienced when you go deep down the sea. However, the reason elevation affects climate and temperature gets colder is this. As you go higher up, the atmosphere experiences less pressure.

Explanation:

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1. A race car accelerates at a rate of 15.6 m/s. If it starts from rest, how much time till it
musickatia [10]

Answer: 5.79 s

Explanation:

Vs=0 m/s starting speed(from rest)

Vf=325 km/h= 325*1000/3600= 90.28 m/s

a=15.6m/s²

Using equation for acceleration  we can find out time :

a=(Vf-Vs)/t

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t=(90.28 m/s-0m/s)/15.6 m/s²

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3 years ago
A 1500-kilogram car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The c
Nutka1998 [239]

1. The acceleration of the car is 3.375 m/s².

2. The force moving the car is 5062.5 N

From the question given above, the following data were obtained:

Mass of car = 1500 Kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

<h3>Acceleration (a) =? </h3><h3>Force (F) =? </h3>

<h3>1. Determination of the acceleration </h3>

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

<h3>Acceleration (a) =?</h3>

a = \frac{v - u}{t} \\\\a = \frac{27 - 0}{8} \\\\a = \frac{27}{8}\\

<h3>a = 3.375 m/s²</h3>

Therefore, the acceleration of the car is 3.375 m/s²

<h3>2. Determination of the force moving the car.</h3>

Mass of car = 1500 Kg

Acceleration (a) = 3.375 m/s²

<h3>Force (F) =?</h3>

<h3>F = ma</h3>

F = 1500 × 3.375

<h3>F = 5062.5 N</h3>

Therefore, the force moving the car is 5062.5 N

Learn more: brainly.com/question/13001406

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