Answer:
magnitude of force on charge 2Q = 
Direction of force on charge = 61 ⁰
Explanation:
The magnitude on the force on the charge can be evaluated by finding the net force acting on the charge 2Q i.e x-component of the net force and the y-component of the net force
║F║ = 
= after considering the forces coming from Q, 3Q and 4Q AND APPLYING COULOMBS LAW
magnitude of force acting on 2Q =
The direction of the force on charge 2Q is calculated as
tan ∅ = 
= 1.8284
therefore ∅ = 
1.8284
= 61⁰
Answer:
The answer to the question is
The distance d, which locates the point where the light strikes the bottom is 29.345 m from the spotlight.
Explanation:
To solve the question we note that Snell's law states that
The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction
n₁sinθ₁ = n₂sinθ₂
y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and
θ₁ = 14.511 °
n₁ = 1.0003 = refractive index of air
n₂ = 1.33 = refractive index of water
Therefore sinθ₂ = 
= 
= 0.1885 and θ₂ = 10.86 °
Since the water depth is 4.0 m we have tanθ₂ = 
or x₂ = 
=
= 20.845 m
d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.
The conclusion is; Cathy's dad has gone fishing.
<h3>What are conclusions in conditional statements?</h3>
A conditional statement is a statement with a hypothesis which is then followed by a conclusion.
A conditional statement has two parts; "if" and "then"
The hypothesis is “if,” part of a conditional statement.
The conclusion is the “then,” part of a conditional statement.
Considering the given conditional statements:
1. If it's Saturday, then Cathy's dad goes fishing.
2. If it's Saturday, then Cathy's dad goes fishing.
Since the if part is true, the conclusion will be, Cathy's dad has gone fishing.
In conclusion, a conditional statement consists of a hypothesis and a conclusion.
Learn more about conditional statements at: brainly.com/question/21170
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Answer:
a = -0.05 m/s² (negative sign shows deceleration)
Explanation:
In order, to find out the minimum average acceleration for a student starting at 5 m/s to slide to the end, we can use 3rd equation of motion. 3rd equation of motion is given as follows:
2as = Vf² - Vi²
where,
a = minimum acceleration required = ?
s = minimum distance covered = 250 m
Vf = Final Speed = 0 m/s (for minimum acceleration the student will barely cover 250 m and then stop)
Vi = Initial Velocity = 5 m/s
Therefore,
2a(250 m) = (0 m/s)² - (5 m/s)²
a = - (25 m²/s²)/(500 m)
<u>a = -0.05 m/s²</u> (negative sign shows deceleration)
B is correct because most of the cells look the same so it's B
