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Mice21 [21]
3 years ago
15

Someone please help!

Physics
1 answer:
NISA [10]3 years ago
8 0
Do you know what's this unit called? it may help figure out how to do it.
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The electrons involved in the formation of a chemical bond are called
tatiyna

Answer: Valence electrons

Valence electrons are those that are in the outermost or superficial layer of the atom, which means they have the highest energy compared to those of the inner layers.

Because of their position, it is easier for these electrons to interact with other atoms of their own element as well as different elements. This is done through the process of forming bonds when being attracted by other atoms.

7 0
3 years ago
Pls help on this one
lidiya [134]

Answer:

D

Explanation:

because 50.0/10.0 = 5.0

5 0
3 years ago
Read 2 more answers
What simple machines are used to create the shovel?
erastovalidia [21]

Answer:

I believe a wedge and a lever

Explanation:

7 0
3 years ago
Transmission Lines and Health. Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the elec
Blababa [14]

Calculate the magnetic field strength at the ground. Treat the transmission line as infinitely long. The magnetic field strength is then given by:

B = μ₀I/(2πr)

B = magnetic field strength, μ₀ = magnetic constant, I = current, r = distance from line

Given values:

μ₀ = 4π×10⁻⁷H/m, I = 170A, r = 8.0m

Plug in and solve for B:

B = 4π×10⁻⁷(170)/(2π(8.0))

B = 4.25×10⁻⁶T

The earth's magnetic field strength is 0.50G or 5.0×10⁻⁵T. Calculate the ratio of the line's magnetic field strength to earth's magnetic field strength:

4.25×10⁻⁶/(5.0×10⁻⁵)

= 0.085

= 8.5%

The transmission line's magnetic field strength is 8.5% of that of earth's natural magnetic field. This is no cause for worry.

8 0
3 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n
qwelly [4]

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × 10^{-21} = 9 × 10^{9} × (n × 1.602 × 10^{-19})² /0.2²

solving for n

n = 759

4 0
3 years ago
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