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3 years ago

Someone please help!

Physics

1 answer:

NISA [10]3 years ago

8 0

Do you know what's this unit called? it may help figure out how to do it.

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Water is a(n) ____ factor in all ecosystem that all living things require.<br> (Fill in the blank)

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Biotic i think is the answer

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3 years ago

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A person's _____________ will change if they move from the Earth to the moon.

Dennis_Churaev [7]

A person's weight will change if they move from Earth to the moon.

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3 years ago

An eagle flies from its perch in a tree to the ground to capture and eat its prey. describe its energy transfromation

ddd [48]

10% energy is transferred from the prey to eagle and 90% energy is lost in the enviorment .

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3 years ago

A baseball pitcher throws a ball at 97.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it

mario62 [17]

Answer:

Explanation:

1 mile=5280 ft

1 hour=3600 seconds

Changing speed from mi/h to ft/s

$97 mi/h \times \frac {5280}{3600}=142.2666667 ft/s\approx 142.27 ft/s$

Time of flight, $t=\frac {distance}{speed}=\frac {60.5}{142.27}=0.425257732 s\approx 0.425 s$

From fundamental kinematics equations

$h=0.5gt^{2}$ where g is acceleration due to gravity whose value is taken as 32.2 ft/s2 and h is the distance

By substitution

$h=0.5\times 32.2\times 0.425^{2}=2.9080625 m\approx 2.91 m$

7 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into th

satela [25.4K]

The tank has a volume of $\dfrac\pi3R^2H$ , where $H=6\,\rm m$ is its height and $R=\dfrac d2=2\,\rm m$ is its radius.

At any point, the water filling the tank and the tank itself form a pair of similar triangles (see the attached picture) from which we obtain the following relationship:

$\dfrac26=\dfrac rh\implies r=\dfrac h3$

The volume of water in the tank at any given time is

$V=\dfrac\pi3r^2h$

and can be expressed as a function of the water level alone:

$V=\dfrac\pi3\left(\frac h3\right)^2h=\dfrac\pi{27}h^3$

Implicity differentiating both sides with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9h^2\,\dfrac{\mathrm dh}{\mathrm dt}$

We're told the water level rises at a rate of $\dfrac{\mathrm dh}{\mathrm dt}=20\,\frac{\rm cm}{\rm min}$ at the time when the water level is $h=2\,\mathrm m=200\,\mathrm{cm}$ , so the net change in the volume of water $\dfrac{\mathrm dV}{\mathrm dt}$ can be computed:

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9(200\,\mathrm{cm})^2\left(20\,\dfrac{\rm cm}{\rm min}\right)=\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}$

The net rate of change in volume is the difference between the rate at which water is pumped into the tank and the rate at which it is leaking out:

$\dfrac{\mathrm dV}{\mathrm dt}=(\text{rate in})-(\text{rate out})$

We're told the water is leaking out at a rate of $10,500\,\frac{\mathrm{cm}^3}{\rm min}$ , so we find the rate at which it's being pumped in to be

$\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}=(\text{rate in})-10,500\,\dfrac{\mathrm{cm}^3}{\rm min}$

$\implies\text{rate in}\approx289,753\,\dfrac{\mathrm{cm}^3}{\rm min}$

4 0

3 years ago