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fenix001 [56]
3 years ago
7

What are the solutions of the equation x4 – 5x2 – 36 = 0? use factoring to solve.

Mathematics
2 answers:
Paul [167]3 years ago
8 0
X^4 - 5x^2 - 36 = 0
(x^2 - 9)(x^2 + 4) = 0  - factor the left side
(x + 3)(x - 3)(x^2 + 4) = 0 - factor (x^2 - 9 as difference of squares)
x + 3 = 0    x - 3 = 0    x^2 + 4 = 0  Set each factor to 0 if any 0 the left side 0
x = -3         x = 3         x^2 = -4
                                   x = 2i or -2i
The roots are 3, -3, 2i, -2i  (Don't know if you need the imaginary roots but I gave you them anyway)
Dmitry [639]3 years ago
8 0
Well if the equation looks like this x^{4} -5 x^{2}-36=0 then you would have four quite long answers.
x=
2.98707487
-2.98707487
1.98055958i
-1.98055958i

The last two have and i at the end for imaginary. Those four numbers would be your answer.
Hope this helps! Don't forget Brainliest! :)
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Which is equivalent to the expression -8 i squared +3?
Lynna [10]

Answer:

Step-by-step explanation:

i² = -1

-8(-1) + 3 = 8 + 3 = 11

3 0
3 years ago
Jorge owes his father $60. After raking the lawn for the month, he has paid him $12, $8, and $9. How much money does Jorge still
Marat540 [252]
12 + 8 + 9 = 29

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Jorge owes his father $31
4 0
3 years ago
What is 698475.50585057 multiplied by three
attashe74 [19]

Answer:

2,095,426.517

Step-by-step explanation:

From the question above we are required to find the product of 698475.50585057 and 3

Therefore the product can be calculated as follows

698475.50585057 × 3

= 2,095,426.517

Hence 698475.50585057 multiplied by 3 is 2,095,426.517

6 0
3 years ago
Given the probability distributions shown to the​ right, complete the following parts.
Elan Coil [88]

Answer:

a) Expected Value for distribution A, E(X) = 3.020

Expected Value for distribution B, E(X) = 0.980

b) Standard deviation of distribution A = 1.157

Standard deviation of distribution B = 1.157

c) In distribution A, the bigger values of x have a higher probability of occurring than the values of distribution B (whose smaller values of x have a higher chance of occurring, hence, the expected value for distribution A is more than that of distribution B.

But according to the corresponding distribution of values, the two distributions have the same exact spread, A in ascending order (with higher values with bigger probability) and B in descending order (lower values have higher probabilities). But the same spread regardless, hence, the standard deviation which shows how data values spread around the mean (centre point) of a distribution is the same for the two distributions.

Step-by-step explanation:

Expected values is given as

E(X) = Σ xᵢpᵢ

where xᵢ = each possible sample space

pᵢ = P(X=xᵢ) = probability of each sample space occurring.

Distributions A and B is given by

X P(X) X P(x)

0 0.04 0 0.47

1 0.09 1 0.25

2 0.15 2 0.15

3 0.25 3 0.09

4 0.47 4 0.04

For distribution A

E(X) = Σ xᵢpᵢ = (0×0.04) + (1×0.09) + (2×0.15) + (3×0.25) + (4×0.47) = 3.02

For distribution B

E(X) = Σ xᵢpᵢ = (0×0.47) + (1×0.25) + (2×0.15) + (3×0.09) + (4×0.04) = 0.98

b) Standard deviation = √(variance)

But Variance is given by

Variance = Var(X) = Σx²p − μ²

where μ = E(X)

For distribution A

Σx²p = (0²×0.04) + (1²×0.09) + (2²×0.15) + (3²×0.25) + (4²×0.47) = 10.46

Variance = Var(X) = 10.46 - 3.02² = 1.3396

Standard deviation = √(1.3396) = 1.157

For distribution B

Σx²p = (0²×0.47) + (1²×0.25) + (2²×0.15) + (3²×0.09) + (4²×0.04) = 2.30

Variance = Var(X) = 2.30 - 0.98² = 1.3396

Standard deviation = √(1.3396) = 1.157

c) In distribution A, the bigger values of x have a higher probability of occurring than the values of distribution B (whose smaller values of x have a higher chance of occurring, hence, the expected value for distribution A is more than that of distribution B.

But according to the corresponding distribution of values, the two distributions have the same exact spread, A in ascending order (with higher values with bigger probability) and B in descending order (lower values have higher probabilities). But the same spread regardless, hence, the standard deviation which shows how data values spread around the mean (centre point) of a distribution is the same for the two distributions.

7 0
3 years ago
Luisa took a job in which her salary can be modeled by the exponential function y = 36,000(1.025)^x, where x is the number of ye
iogann1982 [59]

Answer:

B and D are the correct answer

Step-by-step explanation:

I took the test

8 0
3 years ago
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