Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,



Compound's mass,
= 0.4647 g
Let the compound's formula will be:

Combustion's general equation will be:
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
Now,
x : y : z = 
= 
= 
= 
So that the empirical formula seems to be "C₃H₆O₂".
Answer:
atom are very tiny partical
<span>2.28 kg x 213 kJ/kg = 486 kJ = 4.86E+05 J</span>
Answer:
hope this image is helpful for you
Answer:
If you dissolve 58.44g of NaCl in a final volume of 1 liter, you have made a 1M NaCl solution, a 1 molar solution.
Explanation: