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3 years ago

I have six eggs i crack 2 cook 2 and eat 2. How many do i have left?

Mathematics

1 answer:

alukav5142 [94]3 years ago

3 0

Answer:

Step-by-step explanation:

six in total, ended up cooking two.

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Bobby is making a cake. The recipe calls for 1( 3)/(4) cups of flour for every( 1)/(8) cups of sugar. How many cups of flour is

PilotLPTM [1.2K]

Answer:

5 cups

Step-by-step explanation:

To get 1 cup of sugar, u must add 1/8 by 8. now you have one cup of sugar. But to find out how much flour u need, u also need to multiply 1 3/4 by 8, which gives u 5 cups

5 0

3 years ago

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What are expressions always equivalent to 4(6+2x)

timurjin [86]

24+12x is the answer

4 0

3 years ago

Plz need help fast will mark the brainiest

prohojiy [21]

Answer:

0.0081

Step-by-step explanation:

yes bye that's the answer

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3 years ago

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For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value if it converges.

salantis [7]

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral $\int_{5}^{\infty}\frac{3}{2}x^2dx$

Now after solving the integral

$[\frac{3}{2}\frac{x^3}{3}]$ limit from 5 to infinite

So $[\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty$

As after solving integral we got infinite value so integral will be diverging in nature

7 0

3 years ago