Answer:
Por ejemplo, el petróleo o el carbón son ejemplos de recursos no renovables porque, aunque se forman mediante un proceso natural, este necesita demasiado tiempo. ... Esos combustibles fósiles provienen de materia orgánica, pero tardan cientos de miles de años en producirse.
Answer:
The first question is 4
The second one is 1
Explanation:
Please mark brainliest! Hope it helped!
Answer : The value of 
of the weak acid is, 4.72
Explanation :
First we have to calculate the moles of KOH.
Now we have to calculate the value of of the weak acid.
The equilibrium chemical reaction is:
Initial moles 0.25 0.03 0
At eqm. (0.25-0.03) 0.03 0.03
= 0.22
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[HK]}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BHK%5D%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
Therefore, the value of of the weak acid is, 4.72
Answer:
20.19 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Abundance (A%) = 90.5%
Mass of A = 20 amu
Isotope B:
Abundance (B%) = 9.5%
Mass of B = 22 amu
Average atomic mass =..?
The average atomic mass of the element can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
Average atomic mass = [(20 × 90.5)/100] + [(22 × 9.5)/100]
Average atomic mass = 18.1 + 2.09
Average atomic mass = 20.19 amu
Therefore, the average atomic mass of the element is 20.19 amu
I think answer should be d. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks
