The percentage of water of crystallization in blue vitriol is 36.07%.
M(H₂O) = 2Ar(H) + Ar(O) x g/mol
M(H₂O) = 2 + 16 x g/mol
M(H₂O) = 18 g/mol; molar mass of water
M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol
M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol
M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate
The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%
The percentage of water: 90 g/mol / 249.5 g/mol x 100%
The percentage of water = 36.07%
More about blue vitriol: brainly.com/question/8895853
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For the answer to the question above asking w<span>hat volume of concentrated hydrochloric acid (12.0 M HCl) is required to make 2.0 liters of a 3.0 M HCl solution?</span> The answer is 3.0/12.0 * 2 L = So it's C
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This is an incomplete question, here is a complete question.
The reduction of iron(III) oxide to iron during steel-making can be summarized by this sequence of reactions:
;
;
The net reaction is:
;
Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K be sure you use their standard symbols.
Answer : The equilibrium expression will be:
Explanation :
The intermediate reaction are:
(1) ;
(2) ;
The net reaction is:
;
Now we are multiplying reaction 1 by 3 and reaction 2 by 2 and then adding both the reaction we get the net reaction.
(1) ;
(2) ;
If the equation is multiplied by a factor of '2' or '3', the equilibrium constant will be the power of 2 or 3 of the equilibrium constant of initial reaction.
If the equations are added then the equilibrium constant of the reactions will be multiplied.
Thus the equilibrium expression will be:
28.4 grams of P₂O₅ will be obtained from the interaction of 11.2 liters of oxygen with phosphorus.
Let's consider the following balanced equation.
4 P + 5 O₂ ⇒ 2 P₂O₅
Since the conditions are not specified, we will assume that we are working at standard temperature and pressure. At STP, 1 mole of an ideal gas occupies 22.4 L. The volume of 11.2 L of oxygen at STP, assuming ideal behavior, is:
The molar ratio of O₂ to P₂O₅ is 5:2. The moles of P₂O₅ obtained from 0.500 moles of O₂ are:
The molar mass of P₂O₅ is 141.94 g/mol. The mass corresponding to 0.200 moles of P₂O₅ is:
28.4 grams of P₂O₅ will be obtained from the interaction of 11.2 liters of oxygen with phosphorus.
You can learn more about stoichiometry here: brainly.com/question/22288091
X(OH)₂ + 2HCl = XCl₂ + 2H₂O
n{X(OH)₂}=m{X(OH)₂}/M{X(OH)₂}
n(HCl)=c(HCl)v(HCl)
n{X(OH)₂}=n(HCl)/2
m{X(OH)₂}/M{X(OH)₂}=c(HCl)v(HCl)/2
M{X(OH)₂}=2m{X(OH)₂}/{c(HCl)v(HCl)}
M{X(OH)₂}=2*8.65/{2.50*56.9*10⁻³}=121.6 g/mol
M(OH)=17.0 g/mol
M(X)=121.6-17.0*2=87.6 g/mol ⇒ X=Sr, strontium
Sr(OH)₂ + 2HCl = SrCl₂ + 2H₂O